Number System (Part-5)​​​

Total Questions: 50

41. A number, when divided by 15 and 18 every time, leaves 3 as a remainder, the least possible number is: [SSC CPO 09/11/2022 (Moming)]

Correct Answer: (d) 93
Solution:

42. Find the sum of the numbers between 550 and 700 such that when they are divided by 12, 16 and 24, leave remainder 5 in each case. [SSC CPO 09/11/2022 (Evening)]

Correct Answer: (b) 1887
Solution:

43. If the 9-digit number 72x8431y4 is divisible by 36, what is the value of (x/y - y/x) for the smallest possible value of y, given that x and y are natural numbers?

Correct Answer: (b)
Solution:

44. What are the values of R and M. respectively, if the given number is perfectly divisible by 16 and 11 ? [SSC CPO 10/11/2022 (Morning)]

34R05030M6

Correct Answer: (c) 5 and 5
Solution:

45. If the number 476** 0 is divisible by both 3 and 11, then in the hundredth and tenth places, the non-zero digits are, respectively: [SSC CPO 10/11/2022 (Evening)]

Correct Answer: (d) 8 and 5
Solution:

46. Ramu had to select a list of numbers between 1 and 1000 (including both), which are divisible by both 2 and 7. How many such numbers are there? [SSC CPO 11/11/2022 (Morning)]

Correct Answer: (b) 71
Solution:

47. The sum of the odd divisors of 216 is: [SSC CPO 11/11/2022 (Morning)]

Correct Answer: (c) 40
Solution:

48. A six-digit number is divisible by 198. If the digits are rearranged, even then the number will be divisible by: [SSC CPO 11/11/2022 (Afternoon)]

Correct Answer: (a) 3
Solution:

49. A six-digit number 763254 is divisible by 18. If we subtract five times of 41 from the number, then the new number which is formed will be divisible by: [SSC CPO 11/11/2022 (Afternoon)]

Correct Answer: (b) 7
Solution:763254 - 205 = 763049
So, the new number formed is divisible by 7.

50. Two positive numbers differ by 3951. When the larger number is divided by the smaller number, the quotient is 12 and the remainder is 13. The sum of the digits of the larger number is: [SSC CPO 11/11/2022 (Evening)]

Correct Answer: (b) 16
Solution: