Number System-Railway Maths Part VITotal Questions: 5031. Find the sum of the smallest an the largest positive numbers of 6 digits which contain only digits 0, 4, 6 and each of these digits appears at least once. [RRB NTPC 09/02/2021 (Evening)](a) 1066646(b) 604604(c) 666666(d) 666444Correct Answer: (a) 1066646Solution:Smallest 6-digit number formed using 0,4 and 6 = 400006 Largest 6-digit number formed using 0, 4 and 6 = 666640 Sum = 666640 + 400006 = 10,66,64632. To a number (1/3 - 1/4) is added. From the sum so obtained 1/3 of 1/4 is subtracted and the remainder is 1/3 +, 1/4 Find the number. [RRB NTPC 10/02/2021 (Morning)](a) 2/3(b) 7/12(c) 1/12(d) 4/9Correct Answer: (b) 7/12Solution:Let, number = X { x + ( 1/3 - 1/4 ) } - ( 1/3 × 1/4 ) = ( 1/3 + 1/4 ) { x + ( 1/12 ) } - 1/12 = 7/12 ⇒ x = 7/1233. Find the smallest natural number N such that the product 288 x N is a perfect cube. [RRB NTPC 10/02/2021 (Morning)](a) 8(b) 9(c) 12(d) 6Correct Answer: (d) 6Solution:Factorization of 288 then we get -- 2 × 2 × 2 × 2 × 2 × 3 × 3 For making a perfect cube, 288 will be multiply with (2 × 3) Then 288 × 6 , now we can say that 6 is the smallest natural number.34. Find the sum of all even natural numbers less than 85. [RRB NTPC 10/02/2021 (Evening)](a) 840(b) 1806(c) 1408(d) 4700Correct Answer: (b) 1806Solution:35. Which of the following is equal to 3.14 × 10⁶ ? [RRB NTPC 10/02/2021 (Evening)](a) 3140000(b) 314000(c) 3140(d) 31.40000Correct Answer: (a) 3140000Solution:3.14 × 10⁶ = 314/100 × 1000000 = 314000036. A number, x, when divided by 7 leaves a remainder of 1 and another number, y, when divided by 7 leaves a remainder of 2. What will be the remainder if x + y is divided by 7? [RRB NTPC 10/02/2021 (Evening)](a) 3(b) 4(c) 1(d) 2Correct Answer: (a) 3Solution:Dividend = (Divisor × quotient) +remainder Let us assume p is the quotient when x is divided by 7 and q is the quotient when y is divided by 7. X = (7p) + 1 and Y = (7q) + 2 Therefore X + Y = 7p + 7q + 1 + 2 = 7(p + q) +3 ⇒ (X + Y) when divided by 7 leaves remainder 3.37. Find the greatest four-digit number that is a perfect square. [RRB NTPC 10/02/2021 (Evening)](a) 9801(b) 9999(c) 9000(d) 9008Correct Answer: (a) 9801Solution:The greatest four digit number is 9999. After finding Square root by the long division method we get 198 as remainder, So now we subtract 198 from 9999 to get a perfect square number that is 9999 - 198 = 980138. Out of six consecutive numbers, the sum of the first three numbers is 27. What is the sum of the next three numbers? [RRB NTPC 11/02/2021 (Morning)](a) 12(b) 63(c) 36(d) 10Correct Answer: (c) 36Solution:Let the six consecutive numbers are = x, x + 1 , x + 2 x + 3 , x + 4 , x + 5, x + x + 1 + x + 2 = 27 ⇒ 3x + 3 = 27 ⇒ 3x = 24 ⇒ x = 8 Sum of next three numbers = 3x + 12 = 3 × 8 + 12 = 3639. The value of 1/4 + 1/(4 × 5) + 1/(4 × 5 × 6) correct to four decimal places is. [RRB NTPC 11/02/2021 (Morning)](a) 0.3092(b) 0.3083(c) 0.3150(d) 0.3140Correct Answer: (b) 0.3083Solution:40. How many significant digits are there to the right of the decimal point in the product of 95.75 and 0.02554? [RRB NTPC 11/02/2021 (Morning)](a) 4(b) 5(c) 3(d) 6Correct Answer: (d) 6Solution:95.75 × 0.02554 = 2.445445 the decimal point will be after 6 digits from the rightSubmit Quiz« Previous12345Next »