Number System-Railway Maths Part VII

Total Questions: 50

1. The square root of 18769 consists of how many digits? [RRB NTPC 15/02/2021 (Morning)]

Correct Answer: (b) 3
Solution:

Square root of 18769 = 137
137 consists of 3 digits.

2. The sum of the first 12 multiples of 6 is: [RRB NTPC 15/02/2021 (Morning)]

Correct Answer: (c) 468
Solution:

First multiple of 6 = 6
And 12th multiple of 6 = 72
Sum of 1st 12 multiple of 6
= 6 × (1 + 2 + .............. + 12)

3. Arrange the given fractions in decreasing order. [RRB NTPC 15/02/2021 (Morning)]

Correct Answer: (d) 9/10 , 8/9 , 7/8 ​
Solution:

4. The remainder in the expression 27¾ is: [RRB NTPC 15/02/2021 (Morning)]

Correct Answer: (a) 3
Solution:

5. The sum of two numbers is 20 and the difference between their squares is 80. Select the two numbers from the given options. [RRB NTPC 15/02/2021 (Morning)]

Correct Answer: (d) 12, 8
Solution:

Let the numbers are x and y
A/Q, x + y = 20 ——— (i)
And x²− y²= 80 ——— (ii)
Put x = 20 − y  in equation (ii)

6. Find the two-digit number such that the sum of its digits is 8 and the digits of the number get reversed, when 36 is added to it? [RRB NTPC 15/02/2021 (Evening)]

Correct Answer: (b) 26
Solution:

Let, number = 10x + y
x + y = 8 .....(1)
10x + y + 36 = 10y + x
9(x - y) = -36 ⇒ x - y = -4 .....(2)
From (1) and (2), we get
x = 2, y = 6, Number = 26

7. If the sum of five consecutive multiples of 2 is 660, then find the larger number. [RRB NTPC 15/02/2021 (Evening)]

Correct Answer: (d) 136
Solution:

Here, x is an even number.
Let, numbers are = x, (x + 2), (x + 4), (x + 6), (x + 8)
A/Q, x + (x + 2) + (x + 4) + (x + 6) + (x + 8) = 660,
5x + 20 = 660 ⇒ x = 128
Therefore, the number will be – 128, 130, 132, 134 and 136
Greatest number = 136 and smallest number = 128

8. Calculate the positive number which when added by 15 is equal to 100 times the reciprocal of a number. [RRB NTPC 15/02/2021 (Evening)]

Correct Answer: (c) 5
Solution:

115 + x = 100/x
15x + x² = 100 ⇒ x² + 15x = 100
Then, we get +ve root (x) = 5

9. Find the value of r such that the mean of the first r odd natural numbers is (r²)/16 [RRB NTPC 15/02/2021 (Evening)]

Correct Answer: (a) 16
Solution:

Let, r = 16
then,
r²/16 = (16 × 16)/16 = 16

10. What is the difference between the biggest and the smallest fraction among 2/3, 3/4, 4/5, and 5/6 ? [RRB NTPC 15/02/2021 (Evening)]

Correct Answer: (d) 1/6
Solution:

The difference between the biggest and the smallest fraction
= 5/6 − 2/3 = 1/6