Solution:In (LR9, PU55) ⇒ L + 4 = P, R + 3 = U,
9 × 5 = 55
In (DL5, HP25) ⇒ D + 4 = H, L + 4 = P,
5 × 5 = 25
In (HP7, LT35) ⇒ H + 4 = L, P + 4 = T,
7 × 5 = 35
In (PJ3, TN15) ⇒ P + 4 = T, J + 4 = N,
3 × 5 = 15
We can clearly see in the above expression that all three are following the same logic except (LR9, PU55).