Odd One Out (SSC CGL 2022 Tier – 2)

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{(1^st number × 3) + 3} = 2^nd number
(10 : 33) → {(10 × 3) + 3} = 33
(2 : 9) → {(2 × 3) + 3} = 9
(6 : 21) → {(6 × 3) + 3} = 21
But,
(8 : 29) → {(8 × 3) + 3} = 27 ≠ 29

Hence, (8 : 29) is the correct answer.

{(1^st number × 2) + 4} = 2^nd number
(1 : 6) → {(1 × 2) + 4} = 6

(15 : 34) → {(15 × 2) + 4} = 34
(7 : 18) → {(7 × 2) + 4} = 18
But,

(18 : 42) → {(18 × 2) + 4} = 40 (not 42)

Hence, (18 : 42) is the correct answer.

{1^st number + (1^st number - 1)} = 2^nd number & (1^st number)² = 3^rd number
(11 : 21 : 121) → {11 + (11-1)} = 21 & (11)² = 121
(2 : 3 : 4) → {2 + (2-1)} = 3 & (2)² = 4
(9 : 17 : 81) → {9 + (9-1)} = 17 & (9)² = 81
But,

(7 : 15 : 49) → {7 + (7-1)} = 13 ≠ 15 & (7)² = 49

Hence, (7 : 15 : 49) is the correct answer.