Odd One Out (SSC CHSL 2020 Tier – 1)

Sum of digits of each number is 17
3437 → 3 + 4+ 3 + 7 = 17
7415 → 7 + 4 + 1 + 5 = 17

5453 → 5 + 4 + 5 + 3 = 17

But,

7437 → 7 + 4 + 3 + 7 = 21 ≠ 17

Hence, 7437 is the correct answer.

Middle two numbers are the product of first and last number
2105 → 2 × 5 = 10

4328 → 4 × 8 = 32

3124 → 3 × 4 = 12

But,

6457 → 6 × 7 = 42 ≠ 45

Hence, 6457 is the correct answer.

ILORUZ → I < L < O < R < U < Z = ILORUZ

EGIKOT → E < G < I < K < O < T = EGIKOT

ABEGIJ → A < B < E < G < I < J = ABEGIJ

But,

ASOJIB → A < B < I < J < O < S = ABIJOS ≠ ASOJIB

Hence, ASOJIB is the correct answer.

The sum of the place value of every alphabet is 57
DHSZ → D(4) + H(8) + S(19) + Z(26) = 57

TXCJ → T(20) + X(24) + C(3) + J(10) = 57

GKPW → G(7) + K(11) + P(16) + W(23) = 57

But,

NRJQ → N(14) + R(18) + J(10) + Q(17) = 59 ≠ 57

Hence, NRJQ is the correct answer.

Sum of all the digit of number = 14

6341 → 6 + 3 + 4 + 1 = 14

5423 → 5 + 4 + 2 + 3 = 14

1652 → 1 + 6 + 5 + 2 = 14

But,

6138 → 6 + 1 + 3 + 8 = 18 ≠ 14

Hence, 6138 is the correct answer.

But,

Oslo is the place.

Hence, "Oslo" is the correct answer.

The pattern followed here is :

(2^nd number)² = 1^st number

(289 : 17) → 17² = 289

(225 : 15) → 15² = 225

(484 : 22) → 22² = 484

But,

(322 : 18) → 18² = 324 ≠ 322

Hence, (322 : 18) is the correct answer.

The pattern followed here is :

{1^st letter + 6 = 2^nd letter}, {2^nd letter + 6 = 3^rd letter} & {3^rd letter + 6 = 4^th letter}

PVBH → (P + 6 = V), (V + 6 = B) & (B + 6 = H)

CIOU → (C + 6 = I), (I + 6 = O) & (O + 6 = U)

KQWC → (K + 6 = Q), (Q + 6 = W) & (W + 6 = C)

But,

SYDJ → (S + 6 = Y), (Y + 6 ≠ D) & (D + 6 = J)

Hence, SYDJ is the correct answer.

All numbers are divisible by 7.

But,

348 is not divisible of 7

Hence, 348 is the correct answer.

463, 131 & 229 are all prime numbers.

But,

308 is non prime number.

Hence, 308 is the correct answer.