Odd One Out (SSC CHSL 2021 Tier – 1)

(2^nd number)² × (2^nd number + 1) = (1^st number)

(80 : 4) → {(4)² × (4 + 1)} ⇒ (16 × 5) = 80
(36 : 3) → {(3)² × (3 + 1)} ⇒ (9 × 4) = 36
(12 : 2) → {(2)² × (2 + 1)} ⇒ (4 × 3) = 12

But,

(25 : 5) → {(5)² × (4 + 1)} ⇒ (25 × 5) = 125 ≠ 25

Hence, (25 : 5) is the correct answer.

(1^st number - 2^nd number ) = Number should be multiple of both 1^st & 2^nd number

(12 : 9) → (12 - 9) = 3 which divides both 12 and 9.
(8 : 4) → (8 - 4) = 4 which divides both 8 and 4.
(20 : 25) → (25 - 20) = 5 which divides both 20 and 25.
But,

(4 : 15) → (15 - 4) = 11 which does not divide both 4 and 15.
Hence, (4 : 15) is the correct answer.

[√(1^st number) + {√(1^st number) - 2}] = 2^nd number(16 : 6) → {√16 + (√16 - 2)} ⇒ {4 + (4 - 2)} ⇒ (4 + 2) = 6
(25 : 8) → {√25 + (√25 - 2)} ⇒ {5 + (5 - 2)} ⇒ (5 + 3) = 8
(49 : 12) → {√49 + (√49 - 2)} ⇒ {7 + (7 - 2)} ⇒ (7 + 5) = 12
But,

(4 : 18) → {√4 + (√4 - 2)} ⇒ {2 + (2 - 2)} ⇒ (2 + 0) = 2 ≠ 18

Hence, (4 : 18) is the correct answer.

{(1^st number)² -(1^st number × 2 )} = 2^nd number

(16 : 224) → {16² - (16 × 2)} ⇒ (256 - 32) = 224
(21 : 399) → {21² - (21 × 2)} ⇒ (441 - 42) = 399
(35 : 1155) → {35² - (35 × 2)} ⇒ (1225 - 70) = 1155
But,

(17 : 238) → {17² - (17 × 2)} ⇒ (289 - 34) = 255 ≠ 238
Hence, (17 : 238) is the correct answer.

(Sum of digit of 1^st number) × 2 = 2^nd number

(678 : 42) → {(6 + 7 + 8) × 2} ⇒ (21 × 2) = 42
(546 : 30) → {(5 + 4 + 6) × 2} ⇒ (15 × 2) = 30
(125 : 16) → {(1 + 2 + 5) × 2} ⇒ (8 × 2) = 16
But,

(283 : 28) → {(2 + 8 + 3) × 2} ⇒ (13 × 2) = 26 ≠ 28
Hence, (283 : 28) is the correct answer.

(2^nd number + 2)² =  (1^st number)

(169 : 11) → (11 + 2)² ⇒ 13² = 169
(36 : 4) → (4 + 2)² ⇒ 6² = 36
(9 : 1) → (1 + 2)² ⇒ 3² = 9
But,

(25 : 5) → (5 + 2)² ⇒ 7² = 49 ≠ 25

Hence, (25 : 5) is the correct answer.

{(1^st number)² + 1) ÷ 2} =  (2^nd number)

(3 : 5) → {(3²+ 1) ÷ 2} ⇒ {(9 + 1) ÷ 2} ⇒ (10 ÷ 2) = 5
(7 : 25) → {(7²+ 1) ÷ 2} ⇒ {(49 + 1) ÷ 2} ⇒ (50 ÷ 2) = 25
(5 : 13) → {(5²+ 1) ÷ 2} ⇒ {(25 + 1) ÷ 2} ⇒ (26 ÷ 2) = 13
But,

(1 : 2) → {(1²+ 1) ÷ 2} ⇒ {(1 + 1) ÷ 2} ⇒ (2 ÷ 2) = 1 ≠ 2

Hence, (1 : 2) is the correct answer.

{(1^st number) ÷ 2) + 1}³ =  (2^nd number)

(14 : 512) → {(14 ÷ 2) + 1)}³ ⇒ (7 + 1)³ ⇒ (8)³ = 512
(22 : 1728) → {(22 ÷ 2) + 1)}³ ⇒ (11 + 1)³ ⇒ (12)³ = 1728
(38 : 8000) → {(38 ÷ 2) + 1)}³ ⇒ (19 + 1)³ ⇒ (20)³ = 8000
But,

(46 : 12167) → {(46 ÷ 2) + 1)}³ ⇒ (23 + 1)³ ⇒ (24)³ = 13824 ≠ 12167
Hence, (46 : 12167) is the correct answer.

{(√1^st number) - 3) =  (2^nd number)

(169 : 10) → √169 - 3 = 10
(196 : 11) → √196 - 3 = 11
(64 : 5) → √64 - 3 = 5
But,

(36 : 2) → √36 - 3 ≠ 2

Hence, (36 : 2) is the correct answer.

(56 : 72) → 8(4 - 5)
(32 : 40) → 8(4 - 5)
(64 : 80) → 16(4 - 5)
But,

(48 : 62) → 2(24 - 31)

Hence, (48 : 62) is the correct answer.