Odd One Out (SSC CPO 2020 Tier – 1)

Total Questions: 6

1. Pick the odd one out. [S.S.C CPO 23/11/2020 (Morning)]

Correct Answer: (c) OMSVY
Solution:

The pattern followed here is :

{1st letter + 3 = 2nd letter}, {2nd letter + 3 = 3rd letter}, {3rd letter + 3 = 4th letter} & {4th letter + 3 = 5th letter}

CFILO → (C + 3 = F), (F + 3 = I), (I + 3 = L) & (L + 3 = O)

UXADG → (U + 3 = X), (X + 3 = A), (A + 3 = D) & (D + 3 = G)

ORUXA → (O + 3 = R), (R + 3 = U), (U + 3 = X) & (X + 3 = A)

But,

OMSVY → (O + 3 ≠ M), (M + 3 ≠ S), (S + 3 = V) & (V + 3 = Y)

Hence, OMSVY is the correct answer.

2. Pick the odd one out. [S.S.C CPO 23/11/2020 (Morning)]

Correct Answer: (b) HSNZ
Solution:The pattern followed here is :

{2nd letter = opposite of 1st letter} & {Sum of position value of 3rd & 4th letter = 13}

BYHE → (B ↔ Y) & {H(8) + E(5)} ⇒ 8 + 5 = 13

DWJC → (D ↔ W) & {J(10) + C(3)} ⇒ 10 + 3 = 13

UFAL → (U ↔ F) & {A(1) + L(12)} ⇒ 1 + 12 = 13

But,

HSNZ → (H ↔ S) & {N(14) + Z(26)} ⇒ 14 + 26 = 40 ≠ 13

Hence, HSNZ is the correct answer.

3. Pick the odd one out. [S.S.C CPO 23/11/2020 (Evening)]

Correct Answer: (b) SVAD
Solution:

The pattern followed here is :

{1st letter + 4 = 2nd letter}, {2nd letter + 4 = 3rd letter} & {3rd letter + 3 = 4th letter}

FJNQ → (F + 4 = J), (J + 4 = N) & (N + 3 = Q)

LPTW → (L + 4 = P), (P + 4 = T) & (T + 3 = W)

BFJM → (B + 4 = F), (F + 4 = J) & (J + 3 = M)

But,

SVAD → (S + 4 ≠ V), (V + 4 ≠ A) & (A + 3 = D)

Hence, SVAD is the correct answer.

4. Pick the odd one out. [S.S.C CPO 24/11/2020 (Evening)]

Correct Answer: (b) RUXAE
Solution:

The pattern followed here is :

{1st letter + 3 = 2nd letter}, {2nd letter + 3 = 3rd letter}, {3rd letter + 3 = 4th letter} & {4th letter + 3 = 5th letter}

QTWZC → (Q + 3 = T), (T + 3 = W), (W + 3 = Z) & (Z + 3 = C)

BEHKN → (B + 3 = E), (E + 3 = H), (H + 3 = K) & (K + 3 = N)

HKNQT → (H + 3 = K), (K + 3 = N), (N + 3 = Q) & (Q + 3 = T)

But,

RUXAE → (R + 3 = U), (U + 3 = X), (X + 3 = A) & (A + 3 ≠ E)

Hence, RUXAE is the correct answer.

5. Pick the odd one out. [S.S.C CPO 25/11/2020 (Morning)]

Correct Answer: (d) BSMK
Solution:The pattern followed here is :

Sum of positioning value of all letters = 42

CQLJ → C(3) + Q(17) + L(12) + J(10) ⇒ 3 + 17 + 12 + 10 = 42

DPNH → D(4) + P(16) + N(14) + H(8) ⇒ 4 + 16 + 14 + 8 = 42

GKDT → G(7) + K(11) + D(4) + T(20) ⇒ 7 + 11 + 4 + 20 = 42

But,

BSMK → B(2) + S(19) + M(13) + K(11) ⇒ 2 + 19 + 13 + 11 = 45 ≠ 42

Hence, BSMK is the correct answer.

6. Pick the letter-cluster that is different from the rest. [S.S.C CPO 25/11/2020 (Evening)]

Correct Answer: (c) MNPK
Solution:

The pattern followed here is :

{1st letter + 4 = 3rd letter}, {3rd letter - 4 = 4th letter}

RIVE → (R + 4 = V) & (I - 4 = E)

HSLO → (H + 4 = L) & (S - 4 = O)

DWHS → (D + 4 = H) & (W - 4 = S)

But,

MNPK → (M + 4 ≠ P) & (N - 4 ≠ K)

Hence, MNPK is the correct answer.