Odd One Out (SSC CPO 2022 Tier – 1)

Total Questions: 11

1. Pick the odd one out. [S.S.C CPO 09/11/2022 (Morning)]

Correct Answer: (c) PTY
Solution:The pattern followed here is :

(1st letter + 4 = 2nd letter) & (2nd letter + 6 = 3rd letter)

EIO → (E + 4 = I) & (I + 6 = O)

YCI → (Y + 4 = C) & (C + 6 = I)

DHN → (D + 4 = H) & (H + 6 = N)

But,

PTY → (P + 4 = T) & (T + 6 ≠ Y)

Hence, PTY is the correct answer.

2. Pick the odd one out. [S.S.C CPO 09/11/2022 (Afternoon)]

Correct Answer: (b) JQT
Solution:The pattern followed here is :

HSP → H ↔ S (opposite) & S - 3 = P

FUR → F ↔ U (opposite) & U - 3 = R

LOL → L ↔ O (opposite) & O - 3 = L

But,

JQT → J ↔ Q (opposite) & Q - 3 = N ≠ T

Hence, JQT is the correct answer.

3. Based on the position in the English alphabetical order, three of the following letter-clusters are alike in some manner and one is different. Select the odd letter-cluster. [S.S.C CPO 09/11/2022 (Afternoon)]

Correct Answer: (a) XUSO
Solution:The pattern followed here is :

(1st letter - 3 = 2nd letter), (2nd letter - 3 = 3rd letter) & (3rd letter - 3 = 4th letter)

NKHE → (N - 3 = K), (K - 3 = H) & (H - 3 = E)

MJGD → (M - 3 = J), (J - 3 = G) & (G - 3 = D)

WTQN → (W - 3 = T), (T - 3 = Q) & (Q - 3 = N)

But,

XUSO → (X - 3 = U), (U - 3 ≠ S) & (S - 3 ≠ O)

Hence, XUSO is the correct answer.

4. Based on the position in the English alphabetical order, three of the following letter-clusters are alike in some manner and one is different. Select the odd letter-cluster. [S.S.C CPO 09/11/2022 (Evening)]

Correct Answer: (c) ZTSQ
Solution:The pattern followed here is :

{1st letter - 4 = 2nd letter}, {2nd letter - 2 = 3rd letter} & {3rd letter - 3 = 4th letter}

QMKH → (Q - 4 = M), (M - 2 = K) & (K - 3 = H)

PLJG → (P - 4 = L), (L - 2 = J) & (J - 3 = G)

WSQN → (W - 4 = S), (S - 2 = Q) & (Q - 3 = N)

But,

ZTSQ → (Z - 4 ≠ T), (T - 2 ≠ S) & (S - 3 ≠ Q)

Hence, ZTSQ is the correct answer.

5. Pick the odd one out. [S.S.C CPO 10/11/2022 (Morning)]

Correct Answer: (b) JFK
Solution:The pattern followed here is :

(1st letter - 4 = 2nd letter) and ( 1st letter + 2 = 3rd letter)

XTZ → (X - 4 = T) and (X + 2 = Z)

PLR → (P - 4 = L) and (P + 2 = R)

GCI → (G - 4 = C) and (G + 2 = I)

But,

JFK → (J - 4 ≠ F) and (J + 2 ≠ K) (not follows)

6. Based on the position in the English alphabetical order, three of the following letter-clusters are alike in some manner and one is different. Select the odd letter-cluster. [S.S.C CPO 10/11/2022 (Evening)]

Correct Answer: (a) PSTZ
Solution:The pattern followed here is :

(1st letter + 3 = 2nd letter), ( 2nd letter + 1 = 3rd letter) & (3rd letter + 5 = 4th letter)

ADEJ → (A + 3 = D), (D + 1 = E) & (E + 5 = J)

LOPU → (L + 3 = O), (O + 1 = P) & (P + 5 = U)

FIJO → (F + 3 = I), (I + 1 = J) & (J + 5 = O)

But,

PSTZ → (P + 3 = S), (S + 1 = T) & (T + 5 ≠ Z)

Hence, PSTZ is the correct answer.

7. Pick the odd one out. [S.S.C CPO 10/11/2022 (Evening)]

Correct Answer: (b) EUY
Solution:The pattern followed here is :

{1st letter ↔ 2nd letter (alphabetical opposite)} and {2nd letter + 3 = 3rd letter}

PKN → P ↔ K (opposite) and (K + 3 = N)

In DWZ → D ↔ W (opposite) and (W + 3 = Z)

JQT → J ↔ Q (opposite) and (Q + 3 = T)

But,

EUY → E→not opposite→U, and U + 3 ≠ Y

Hence, EUY is the correct answer.

8. Based on the position in the English alphabetical order, three of the following letter-clusters are alike in some manner and one is different. Select the odd the letter-cluster. [S.S.C CPO 11/11/2022 (Morning)]

Correct Answer: (a) JHFA
Solution:The pattern followed here is :

(1st letter - 2 = 2nd letter), (2nd letter - 3 = 3rd letter) & (3rd letter - 4 = 4th letter)

MKHD → (M - 2 = K), (K - 3 = H) & (H - 4 = D)

XVSO → (X - 2 = V), (V - 3 = S) & (S - 4 = O)

NLIE → (N - 2 = L), (L - 3 = I) & (I - 4 = E)

But,

JHFA → (J - 2 = H), (H - 3 ≠ F) & (F - 4 ≠ A)

Hence, JHFA is the correct answer.

9. Pick the odd one out. [S.S.C CPO 11/11/2022 (Morning)]

Correct Answer: (a) ROL
Solution:The pattern followed here is :

(1st letter + 3 = 2nd letter), (2nd letter - 6 = 3rd letter)

RUO → (R + 3 = U) & (U - 6 = O)

VYS → (V + 3 = Y) & (Y - 6 = S)

PSM → (P + 3 = S) & (S - 6 = M)

But,

ROL → (R + 3 ≠ O) & (O - 6 ≠ L)

Hence, ROL is the correct answer.

10. Pick the odd one out. [S.S.C CPO 11/11/2022 (Evening)]

Correct Answer: (c) CJI
Solution:The pattern followed here is :

(1st letter + 6 = 2nd letter) & (2nd letter - 2 = 3rd letter)

JPN → (J + 6 = P) & (P - 2 = N)

MSQ → (M + 6 = S) & (S - 2 = Q)

QWU → (Q + 6 = W) & (W - 2 = U)

But,

CJI → (C + 6 ≠ J) & (J - 2 ≠ I)

Hence, CJI is the correct answer.