Solution:The acceleration due to gravity on the surface of the Earth, g, is given by the formula:g = (GM)/(R²)
where
G is the gravitational constant,
M is the mass of the Earth,
R is the radius of the Earth.
If the radius R decreases by 1%, the new radius R' is: R' = 0.99R
The new acceleration due to gravity g' will be:
g prime = GM (R)² = (GM)/(0.99R)² = (GM)/(0.9801R²)
Thus :
g' = g/0.9801 \approx 1.0204g
This shows that the acceleration due to gravity increases by approximately 2%.