QUADRATIC EQUATIONS AND INEQUATIONS (CDS)Total Questions: 6761. In solving a problem, one student makes a mistake in the coefficient of the first degree term and obtains -9 and -1 for the roots. Another student makes a mistake in the constant term of the equation and obtains 8 and 2 for the roots. The correct equation was [2014 (I) Morning Shift](a) x² + 10x + 9 = 0(b) x² - 10x + 16 = 0(c) x² - 10x + 9 = 0(d) None of the aboveCorrect Answer: (c) x² - 10x + 9 = 0Solution:When mistake is done in first degree term, then the roots of the equation are -9 and -1.62. If m and n are the roots of the equation 27ax² + bx + c = 0, then the equation whose roots are (m² + 1) / m and (n² + 1) / n is [2014 (I) Morning Shift](a) acx² + (ab + bc)x + b² + (a - c)² = 0(b) acx² + (ab bc)x + b² + (a - c)² = 0(c) acx² + (ab bc) x + b² - (a - c)² = 0(d) acx² + (ab + bc)x + b² - (a - c)² = 0Correct Answer: (a) acx² + (ab + bc)x + b² + (a - c)² = 0Solution:For the given equation ax² + bx + c = 0, m and n are the roots. 63. The value of x² - 4x + 11 can never be less than [2014 (I) Morning Shift](a) 7(b) 8(c) 11(d) 22Correct Answer: (a) 7Solution:Let f (x) = x² - 4x + 1164. The expression 2x³ + x² - 2x - 1 is divisible by [2014 (I) Morning Shift](a) x + 2(b) 2x + 1(c) x - 2(d) 2x - 1Correct Answer: (b) 2x + 1Solution:65. If x + y = 5 , y + z = 10 and z + x = 15 then which one of the following is correct? [2014 (I) Morning Shift](a) z > x > y(b) z > y > x(c) x > y > z(d) x > z > yCorrect Answer: (a) z > x > ySolution:Given equations66. If the roots of the equation (a² - bc) x² + 2(b² - ac) x + (c² - ab) = 0 are equal, where b ≠ 0 , then which one of the following is correct? [2014 (I) Morning Shift](a) a + b + c = abc(b) a² + b² + c² = 0(c) a³ + b³ + c³ = 0(d) a³ + b³ + c³ = 3abcCorrect Answer: (d) a³ + b³ + c³ = 3abcSolution:Given equation is (a² - bc) x² + 2(b² - ac) x + (c² - ab) = 067. If the roots of the equation Ax² + Bx + C = 0 are -1 and 1, then which one of the following is correct? [2014 (I) Morning Shift](a) A and C are both zero(b) A and B are both positive(c) A and C are both negative(d) A and Care of opposite signsCorrect Answer: (d) A and Care of opposite signsSolution:Given equation is Ax² + Bx + C = 0 ...(i)Submit Quiz« Previous1234567