Solution:Given R₁ = 2 Ω , R₂ = 3 Ω , and V = 15 Volt If the resistances are connected in series, the current is the same across all resistances.
Now, equivalent resistance,
R = R₁+ R₂ = 2 Ω + 3 Ω = 5 Ω.
Using Ohm’s law, V = IR ⇒ I = V/R = 15 / 5 = 3 A. So the value of current flowing in R₂ = 3 A.