Correct Answer: (d) increasing cross sectional area of the conductor
Solution:Resistance of a conductor,
R = ρ l/A.
Resistance is inversely proportional to the area of the cross - section of the conductor i.e., the more the area of the cross-section of the conductor, the less is the resistance. In a parallel combination of resistors,
1/R = 1/r₁ + 1/r₂
Hence, the effective resistance in a parallel combination of resistors decreases.