Solution:Magnitude of the magnetic field produced inside a solenoid is B = (𝜇ₒ ni) /𝑙 . where i is the current of the solenoid, n is the number of turns the solenoid has, l is the length of the solenoid, and 𝜇ₒ (permeability of free space) = 4𝜋 × 10⁻⁷ T·m/A. So, B depends upon ‘n’ , ‘i’ and ‘𝑙’