Railway Science (Physics-Work, Energy and Power) (Part-III)Total Questions: 5031. If a person moves a trolley for a distance of 10 m with a force of 50 N, then the work done is : [RRB Group D 27/09/2018 (Morning)](a) 0.2 J(b) 5 J(c) 20 J(d) 500 JCorrect Answer: (d) 500 JSolution:Given that, Force acting on the trolley (F) = 50 N. Distance travelled by trolley (s) = 10 m. Total work done, W = F × s = 50 × 10 = 500 J.32. An object of mass 20 kg is moving with a constant velocity of 8 ms⁻¹ . The kinetic energy of the object will be: [RRB Group D 27/09/2018 (Afternoon)](a) 640 J(b) 640 ms⁻¹(c) 640 Pa(d) 640 NCorrect Answer: (a) 640 JSolution:Given that, mass (m)= 20 kg, Velocity = 8 ms⁻¹ . Kinetic energy = 1/2 × m × v² = 1/2 × 20× 8² = 640 J.33. An object has a potential energy of 400 J with a mass of 20 kg and gravity of 10 N kg⁻¹. The height of the object is: [RRB Group D 28/09/2018 (Morning)](a) 0.5 m(b) 4m(c) 1 m(d) 2 mCorrect Answer: (d) 2 mSolution:Given that, Potential energy (U)= 400 J, mass of a body (m) = 20 kg, gravitational acceleration (g)= 10 N/kg or m/sec² , height (h)= ? Potential energy (U) = mgh 400 = 20 × 10 × h ⇒ h = 2 m.34. The kinetic energy of an object of mass 10 kg moving with a velocity of 6 ms⁻¹ is: [RRB Group D 28/09/2018 (Evening)](a) 180J(b) 80J(c) 360J(d) 18JCorrect Answer: (a) 180JSolution:Given that, Mass (m) = 10 kg, Velocity (v) = 6 m/s. The Kinetic Energy of a body is, K.E. = 1/2 mv² = 1/2 × 10 × 6² = 180 J.35. An object moving with a uniform velocity of 4 ms⁻¹ has kinetic energy of 120 J. Find the mass of the object in it. [RRB Group D 01/10/2018 (Morning)](a) 15 kg(b) 1.5 N(c) 30 N(d) 30 kgCorrect Answer: (a) 15 kgSolution:Given, 𝑣 = 4 ms⁻¹, K.E. = 120 J Now, mass (m) = 2 𝐾.𝐸./𝑣² = 2 × 120 / 4² = 15 kg.36. If a factor W does work in time t, then its power (p) will be: [RRB Group D 01/10/2018 (Afternoon)](a) Time-work (t-W)(b) Time × Work (t × W)(c) Work/Time (W/t)(d) Time/Work (t/W)Correct Answer: (c) Work/Time (W/t)Solution:Power is defined as the rate of doing work or the rate of transfer of energy. It is a scalar quantity. SI unit- watt (W). Dimensional Formula - [M¹L²T ⁻³].37. The kinetic energy of an object of mass m moving with a speed of 5 ms⁻¹ is 25 J. What will be its kinetic energy if its speed doubles? [RRB Group D 01/10/2018 (Afternoon)](a) 100 J(b) 50 J(c) 100 N(d) 50 NCorrect Answer: (a) 100 JSolution:Kinetic energy(KE) = 1/2 mv² ⇒ KE ∝ v² . ⇒ If velocity is doubled the kinetic energy becomes 4 times. ⇒ Kinetic energy = 25 × 4 = 100 J.38. An object moving with a uniform velocity of 4ms⁻¹ possesses kinetic energy of 120 J. Find the mass of the object. [RRB Group D 01/10/2018 (Evening)](a) 15 N(b) 15 W(c) 15 kg(d) 15 PaCorrect Answer: (c) 15 kgSolution:39. An object of mass 12 kg is at a certain height above the ground. If the potential energy of the object is 480 J. find the height at which the object is with respect to the ground. Given, g=10 ms⁻² [RRB Group D 03/10/2018 (Afternoon)](a) 5 m(b) 8 m(c) 4 m(d) 6 mCorrect Answer: (c) 4 mSolution:Given that, the object of Mass (m) = 12 kg, Potential energy= 480 J, Acceleration of gravity (g)= 10 ms⁻², Height (h) = ? We know that, Potential energy = mgh = 12 × 10 × h. ⇒ 480 = 12 × 10 × h ⇒ h = 4 m.40. A coolie lifts a load of 11 kg from the ground and places it on his head, 1.5 m above the ground. How much work is done by the coolie? (g = 10 ms⁻²)? [RRB Group D 03/10/2018 (Evening)](a) 100 N(b) 155 J(c) 165 J(d) 150 JCorrect Answer: (c) 165 JSolution:Given that, m = 11 kg, h = 1.5 m, g = 10 m/s² . W = mgh = 11 × 1.5 × 10 = 165 J.Submit Quiz« Previous12345Next »