Railway Science (Physics-Work, Energy and Power) (Part-IV)Total Questions: 501. An object of mass 20 kg is moving with a uniform velocity of 10 ms⁻¹ . What is the kinetic energy possessed by the object? [RRB Group D 05/10/2018 (Evening)](a) 1000 N(b) 1000 Nm⁻²(c) 1000 J(d) 1000 PaCorrect Answer: (c) 1000 JSolution:Given, Mass = 20 kg, Velocity = 10 m/s. Kinetic Energy = 1/2 mv² = 1/2 × 20 × 100 = 1000 J.2. A laborer picks up a 10 kg object from the ground and places it 1.2 m above his head. Calculate the work done by him on the goods. (g = 10 ms⁻²) [RRB Group D 08/10/2018 (Morning)](a) 120 J(b) 155 J(c) 150 J(d) 140 JCorrect Answer: (a) 120 JSolution:Given that, Mass = 10 kg, g = 10 ms⁻², Height (h) = 1.2 m. ∵ Work done = Change in potential energy = mgh. ∴ W = mgh = 10 × 10 × 1.2 ⇒ W = 120 J.3. An object of mass 15 kg is moving with a velocity of 6 m/s. What is the kinetic energy possessed by the object? [RRB Group D 09/10/2018 (Morning)](a) 270 J(b) 270 ms(c)187.5 J(d)187.5Correct Answer: (a) 270 JSolution:Given that, Mass (m) = 15 kg, Velocity (v) = 6 ms⁻¹ . Using the equation of Kinetic energy, Kinetic Energy = 1/2 mv² Kinetic Energy = 1/2 × 15 × 36 = 270 J.4. A force of 125 N is acting on an object. The object is moved 5 meters in the direction of the force. [RRB Group D 09/10/2018 (Morning)](a) 625 Pa(b) 625 J(c) 625 N(d) 625 WCorrect Answer: (b) 625 JSolution:Given, Force, F = 125 N Displacement, s = 5m Work done = Force (F) × Displacement (s) = 125 × 5 = 625 J.5. An object of mass 15 kg is moving with a uniform velocity of 8 ms⁻¹ . What is the kinetic energy of that object? [RRB Group D 09/10/2018 (Afternoon)](a) 480 J(b) 180.5 J(c) 480 ms(d) 187.5 JCorrect Answer: (a) 480 JSolution:6. The kinetic energy of an object is 120 J and mass is 15 kg. Find the velocity of the object. [RRB Group D 09/10/2018 (Afternoon)](a) 4 ms¹(b) 4 ms⁻¹(c) 4 ms⁻²(d) 4 ms²Correct Answer: (b) 4 ms⁻¹Solution:7. An object of mass 15 kg is moving with a uniform velocity of 2 m𝑠⁻¹ What is the kinetic energy possessed by the object ? [RRB Group D 09/10/2018 (Evening)](a) 17.5 J(b) 187.5 ms(c) 187.5 J(d) 30 JCorrect Answer: (d) 30 JSolution:Given that, mass (m) = 15 kg, velocity (v) = 2 ms⁻¹ Using the equation of Kinetic energy, Kinetic Energy = 1/2 mv² Kinetic Energy = 1/2 × 15 × 2² = 30 J.8. An object of mass 10 kg is moving with a uniform velocity of 5 ms⁻¹ . How much kinetic energy has that object possessed? [RRB Group D 10/10/2018 (Morning)](a) 180.5 J(b) 125 J(c) 187.5 J(d) 187.5 msCorrect Answer: (b) 125 JSolution:Given : Mass (m) = 10 kg, Velocity (v) = 5 m/s. Kinetic energy, KE = ? Kinetic Energy (K.E.) = 1/2 × mv² K.E. = 1/2 × 10 × (5)² = 1/2 × 10 × 25 ⇒ = 125 J.9. A car covers a distance of 100 m with a constant force of 50 N. So the work done by the car is: [RRB Group D 10/10/2018 (Evening)](a) 50J(b) 500J(c) 5000J(d) 50000JCorrect Answer: (c) 5000JSolution:Given that : Distance traveled by car (d) = 100 m, Force (F) = 50 N Work done by car (W) = F × d = 100 × 50 = 5000 J.10. An object of mass 13 kg is moving with a uniform velocity of 5 ms⁻¹ . What is the kinetic energy possessed by the object? [RRB Group D 11/10/2018 (Morning)](a) 187.5 J(b) 17.5 J(c) 162.5 J(d) 162.5 msCorrect Answer: (c) 162.5 JSolution:Given, Mass (m) = 13 kg, Velocity (v) = 5 m/s Kinetic Energy = 1/2 mv² = 1/2 × 13 × 5 × 5 = 162.5 J.Submit Quiz12345Next »