Solution:Let the unit's digit be x and ten's digit be y.Then,
The number = 10y + x
On interchanging the digits, new number = 10x + y From statement I,
10y + x - 10x - y = 27
⇒ 9y - 9x = 27 ⇒ y - x = 3
From statements II and III, similar relation is obtained, hence many such numbers are possible.