RBI OFFICER GRADE ‘B’ PHASE-I EXAM Held on : 06.03.2021 (Shift-I) (Part-I)

Total Questions: 50

41. Study the following information carefully and answer the questions given below :

From the questions (41-45)
Twelve persons are sitting in two parallel rows containing six persons in each row, in such a way that there is an equal distance between adjacent persons. In the Row-1, S, Y, T, J, B and N are seated and all of them are facing south. In the Row-2, P, R, L, K, O and A are seated and all of them are facing north. Therefore, in the given seating arrangement, each member seated in a row faces another member of the other row.

• P is sitting second to the right of O. Only one person is sit- ting between A and L. Neither S nor B sits at the extreme end of the line.
• A is not an immediate neighbour R. P does not face N. Neither A nor L faces B.
• L does not sit at the extreme end of the line. Only one person sits between Y and N. S is sitting third to the left of B. Neither P nor O faces B or S.
•P does not sit at the extreme end of the line. T does not face P. T does not sit at the extreme end of the line.
Four of the following five are alike in a certain way and hence they form a group. Which one does not belong to that group ?

Correct Answer: (1) K
Solution:

Except K, the other four persons are sitting at the ends of the rows.

42. Study the above information carefully and answer the questions.

Who among the following sits exactly between B and T ?

Correct Answer: (4) Y
Solution:

Y is sitting exactly between B and T.

43. Study the above information carefully and answer the questions.

Who among the following sits third to the right of J ?

Correct Answer: (2) Y
Solution:

Y is sitting third to the right of J.

44. Study the above information carefully and answer the questions.

Who among the following does face R ?

Correct Answer: (5) B
Solution:

B is facing R.

45. Study the above information carefully and answer the questions.

Who among the following is sitting fourth to the left of K ?

Correct Answer: (3) O
Solution:

O is sitting fourth to the left of K.

46. Study the following information carefully and answer the questions given below :

From the questions (46-50)
Below are given some statements regarding the rules of Syllogism. Select the appropriate Conclusion(s) in each question.

• A @ B : All As are Bs.
• A + B : Some As are Bs.
• A # B : Some As are not Bs.
• A ! B : No A is B.
• A % B : Some As being Bs is a possibility.
• A > B : All As being Bs is a possibility.

Statement :
L + N > R
Conclusions :
 I. All Ls being Rs is a possibility.
II. Some Rs are not Ns.
III. Some Ns are Ls.

Correct Answer: (1) Only Conclusion I and Conclusion III follow
Solution:

(i) All As are Bs ⇒ Universal Affirmative (A-type).
(ii) Some As are Bs ⇒ Particular Affirmative (I-type).
(iii) No A is B ⇒ Universal Negative (E-type).
(iv) Some As are not Bs ⇒ Particular Negative (O-type).
L + N : Some Ls are Ns.
After combining venn diagrams III and IV, we get :
Venn diagram VI supports the Conclusion I.
Conclusion III is the Converse of “Some Ls are Ns”.

47. Study the above information carefully and answer the questions.

Statement :
Y @ P % T
Conclusions :
I. All Ps being Ys is a possibility.
II. Some Ts being Ys is a possibility.
III. Some Ts are not Ps.

Correct Answer: (4) Only Conclusion I and Conclusion II follow
Solution:

(i) All As are Bs ⇒ Universal Affirmative (A-type).
(ii) Some As are Bs ⇒ Particular Affirmative (I-type).
(iii) No A is B ⇒ Universal Negative (E-type).
(iv) Some As are not Bs ⇒ Particular Negative (O-type).
Y @ P : All Ys are Ps.
P % T : Some Ps being Ts is a possibility.

After combining the venn diagrams I and IV, we get :
Venn diagram VI supports the Conclusion II.
Venn diagram II supports the Conclusion I.

48. Study the above information carefully and answer the questions.

Statement :
Z + H @ L
Conclusions :
I. All Zs are Hs.
II. Some Hs are Ls.
III. Some Ls are Zs.

Correct Answer: (3) Only Conclusion II and Conclusion III follow
Solution:

(i) All As are Bs ⇒ Universal Affirmative (A-type).
(ii) Some As are Bs ⇒ Particular Affirmative (I-type).
(iii) No A is B ⇒ Universal Negative (E-type).
(iv) Some As are not Bs ⇒ Particular Negative (O-type).
Z + H : Some Zs are Hs.
H @ L : All Hs are Ls.
I + A ⇒ I-type of Conclusion “Some Zs are Ls”.
Conclusion III is the Converse of it.
Conclusion II is the Implication of “All Hs are Ls”.

49. Study the above information carefully and answer the questions.

Statement :
M % L > B
Conclusions :
 I. All Ls are Bs.
II. Some Ms being Bs is a possibility.
III. All Bs are Ls.

Correct Answer: (2) Only Conclusion II follows
Solution:

(i) All As are Bs ⇒ Universal Affirmative (A-type).
(ii) Some As are Bs ⇒ Particular Affirmative (I-type).
(iii) No A is B ⇒ Universal Negative (E-type).
(iv) Some As are not Bs ⇒ Particular Negative (O-type).
M % L : Some Ms being Ls is a possibility.
L > B : All Ls being Bs is a possibility.
I + A ⇒ I-type of Conclusion “Some Ms are Bs”.
This is the Conclusion II.

50. Study the above information carefully and answer the questions.

Statement :
G # K + M
Conclusions :
I. Some Ks are not Gs.
II. All Ms being Gs is a possibility.
III. Some Gs being Ks is a possibility.

Correct Answer: (5) Only Conclusion II and Conclusion III follow
Solution:

(i) All As are Bs ⇒ Universal Affirmative (A-type).
(ii) Some As are Bs ⇒ Particular Affirmative (I-type).
(iii) No A is B ⇒ Universal Negative (E-type).
(iv) Some As are not Bs ⇒ Particular Negative (O-type).
G # K : Some Gs are not Ks.
K + M : Some Ks are Ms.

After combining the venn diagrams II and V, we get :

Venn diagram VII supports the Conclusion II and Conclusion III.