Solution:In the word “PARAGLIDING” there are 11 letters in which there are 4 vowels (2 A’s and 2 I’s) and 7 consonants (2 G’s and each of P, R, L, D, N)
Considering vowels as one letter, the number of letters becomes 8 which can be arranged in
8!/2! ways = 8 × 7 × 6 × 5 × 4 × 3 = 20160 ways
Vowels A and I appear twice, so vowels can be arranged in
4!/(2!×2!) ways = 6 ways
Required number of ways = 20160 × 6 = 120960