Soil Mechanics and Foundation Engineering (Part-2) (General Engineering) (SSC JE)

Total Questions: 50

21. A soil has a liquid limit of 40% and plasticity index of 20%. The plastic limit of the soil will be– [RRB JE 29.08.2015 (Shift-II) ]

Correct Answer: (a) 20%
Solution:

22. In a particular soil sample, laboratory analysis has yielded the following results– [RRB JE 29.08.2015 (Shift-II) ]

A. Sand - 20%
B. Silt - 30%
C. Clay - 50%
Without using the textural chart, the correct textural classification of the soil would be–

Correct Answer: (d) Clay
Solution:

Textural chart classification–
• In this method, classification of soil is done on the basis of relative % of clay, silt and sand present in the soil which is further read from the textural chart.
• To use the chart for the given% of three constituent primary a soil, lines are drawn parallel to the three side of an equilateral triangle and their common point of intersection is noted to fall in a particular region of textural chart.

23. The property of a soil which allows it to be deformed rapidly, without elastic rebound and without volume changes is called as : [RRB S.S.E. 03.09.2015 (Shift-I) ]

Correct Answer: (d) Plasticity
Solution:

Plasticity of soil is its ability to under go deformation without cracking or fracturing. The main engineering properties of soils are permeability compressibility and shear strength.

24. If the water table is likely to permanent remain at or below a depth of sum of the depth and width of the foundation beneath the ground level supporting the footing, then the water table correction used in the bearing capacity equation is [RRB S.S.E. 03.09.2015 (Shift-I) ]

Correct Answer: (a) 1
Solution:If water table is below the point Y then the water table correction factor is one.

25. The soil having uniformly co-efficient more than 10 is called [RRB JE (Ranchi) 04.01.2015 ]

Correct Answer: (d) Well graded
Solution:

The soil having uniformly co-efficient more than 10 is called well graded.

26. The ratio expressed as a percentage of dry unit weight of a soil to maximum unit weight (density) obtained in a laboratory compaction test is called [RRB JE (Ranchi) 04.01.2015 ]

Correct Answer: (d) Percent compaction
Solution:

This is specification for relative compaction, which can be expressed as
Where,
R = relative compaction
• For the compaction of granular soils, specifications sometimes are written in terms of the required relative density or the required relative compaction.

27. In general, consolidation of soil involves which of the following [RRB S.S.E. 03.09.2015 (Shift-III) ]

Correct Answer: (c) Application of static load
Solution:

Application of static load–
• Consolidation is a process by which soils decrease in volume.
• According to Karl Terzaghi consolidation is any process which involves decrease in water content of a saturated soil without replacement of water by air.
• In general it is the process in which reduction in volume takes place by expulsion of water under long term static loads.
• It occurs when stress is applied to a soil that causes the soil particles to pack together more tightly therefore reducing its bulk volume.

28. If a 6 m high retaining wall retains dry sand of unit weight 18 kN/cum and if the coefficient of earth pressure at rest is 0.5, then the lateral earth pressure at a depth of 6 m will be [RRB S.S.E. 03.09.2015 (Shift-III) ]

Correct Answer: (a) 54
Solution:

29. For a soil, the water content where further loss of moisture will not result in any more volume reduction is called as : [RRB S.S.E. (Secunderabad) 01.09.2015 (Shift-I) ]

Correct Answer: (b) Shrinkage limit
Solution:

Shrinkage limit–
• Shrinkage limit is defined as the maximum water content at which a reduction involves content will not cause a decrease in the volume of soil mass

30. The degree of compaction for sand is usually defined in terms of : [RRB S.S.E. (Secunderabad) 01.09.2015 (Shift-I) ]

Correct Answer: (a) Relative density
Solution:

Relative density is used to indicate the degree of compaction for cohesionless soil. It is given as–