Correct Answer: (a) 48 min
Solution:Let the usual speed of the man be 5x m/min and usual time be y min.
Distance covered by the man = 5xym
Speed of man = (4/3) × 5𝓍
= 4𝓍 m/min
∴ Distance covered by the man
= 4𝓍(y + 12)m
∴ Distance remains same
⇒ 5𝓍y = 4𝓍(y + 12)
5y = 4y + 48
y = 48min