SOLVED PAPER 2022 (CDS) (II) (Elementary Mathematics)Total Questions: 10091. Solved(a)(b)(c)(d)Correct Answer: (b)Solution:92. Solved(a) a + b = c + d(b) a + c = b + d(c) a - b - c + d = 0(d) a + b + c + d = 0Correct Answer: (d) a + b + c + d = 0Solution:93. If (a³ + b³) is proportional to (a² - b²) then (a² - ab + b²) is proportional to(a) (a - b)(b) (a + b)(c) (a + ab + b)(d) (a³ - b³)Correct Answer: (a) (a - b)Solution:Given, a³ +b³ ∝ (a² - b²) a³ + b³ = k(a² - b²) (a + b)³ - 3ab(a + b) = k(a² - b²) (a + b) (a² - ab + b²) = k(a² - b²) a² - ab + b² = k(a - b) ∵ a² - ab + b² is proportional to (a - b).94. Solved(a) 8(b) 9(c) 10(d) 12Correct Answer: (c) 10Solution:95. What is the HCF of (x⁸ - y⁸) and (x⁷ - y⁷ + x⁵ y² - x² y⁵) ?(a) (x² + y²)(b) (x² - y²)(c) (x³ - y³ - x² y + xy²)(d) (x³ - y³ + x² y - xy²)Correct Answer: (a) (x² + y²)Solution:Here, x⁸ - y⁸ = (x⁴ + y⁴) (x² + y²) (x + y) (x - y) = x⁷ - y⁷ + x⁵ y² - x² y⁵ = x⁵ (x² + y²) - y⁵ (x² + y²) = (x⁵ - y⁵) (x² + y²) Hence, HCF = x² + y²96. If the sum of the square of the roots of the equation x² - 14x + k = 0 is 100, then what is the value of k?(a) 42(b) 48(c) 52(d) 56Correct Answer: (b) 48Solution:Let α, β be the roots of the equation. α² + β² = 100 ⇒ (α² + β²) - αβ = 100 ⇒ 196 - 2k = 100 ⇒ 96 = 2k ∴ k = 4897. If (x + k) is the HCF of x² + px + q and x² + qx + p where p ≠ q then what is the value of k?(a) -1(b) 0(c) ½(d) 1Correct Answer: (a) -1Solution:Given equation, x² + px + q = 0 x² + qx + p = 0 Let k is a root of equation, k² - pk + q = 0 k² - qk + p = 0 ⇒ (q - p)k + (q - p) = 0 k = - 198. If three times the greater of two numbers is divided by the smaller number, the quotient will be 6 and the remainder will be 6. If five times the smaller number is divided by the greater number, the quotient will be 2 and the remainder will be 3. What is the difference between the numbers?(a) 8(b) 9(c) 10(d) 12Correct Answer: (b) 9Solution:Let the two numbers be x and y and x > y According to the question, 3x = 6y + 6 x = 2(y + 1) x = 2y + 2 ...(i)Now, 5y = 2x + 3 2x = 5y - 3 ...(ii) In Equations (i) × 2 we get 2x = 4y + 4 and put the value of 2x in Equations (ii) 4y + 4 = 5y - 3 y = 7 Put the value of y in Equations (i) x = 2y + 2 = 2 × 7 + 2 = 16 Now, x - y = 16 - 7 = 999. Consider the following statements:1. (ab + bc + ca) is a factor of a² (b - c)³ + b² (c - a)³ + c² (a - b)³. 2. (a + b + c) is a factor of a² (b - c)³ + b² (c - a)³ + c² (a - b)³.Which of the statements given above is/are correct?(a) Only 1(b) Only 2(c) Both 1 and 2(d) Neither 1 nor 2Correct Answer: (a) Only 1Solution:100. Solved(a)(b)(c)(d)Correct Answer: (d)Solution:Submit Quiz« Previous12345678910