Solution:Here, a square and a rectangle
have same perimeter.
Let side of square be x cm and
dimension of rectangle be length y,
and breadth z.4(y + z) = 4x
y + z = x, .....(i)
According to the question,
(Area of a square)2
- (Area of rectangle)² = 1
x² - (yz)² = 1
⇒ (y + z)² - (yz)² = 1
⇒ (y + z - yz) (y + z + yz) = 1
If yz = 0 and y + z = 1
So, the length of the rectangle
exceeds its breadth by 1 cm.