Solution:Given, N = (12)⁶ × (3)⁸ × (5)³
= 2¹² × 3¹² × 5³
= (2 × 2 × 3)⁶ × (3)⁸ × (5)³1. Number of odd factor of N
= Power of all odd numbers + 1
= (14 + 1)(3 + 1)
(∵ Here the power of 3 is 14 and the
power of 5 is 3. Will not take the
power of 2 as it is an even number)
= 15 × 4 = 60
Hence, Statement 1 is true.
2. Number of even factors of N
= (Power of all even numbers
+ power of all odd numbers + 1)
= (12)(14 + 1)(3 + 1)
= 12 × 15 × 4
Hence, Statement 2 is also true.
Then correct option will be (c).