Correct Answer: (c) Both I and II
Solution:P = n(n + 1)(n + 2)(n + 3) + 1
Here, n, (n + 1) (n + 2) (n + 3) are 4 consecutive natural number.
So n(n + 1)(n + 2)(n + 3) is an even number.
⇒ P is always odd.
So, Statement I is correct.
P = n(n + 1)(n + 2)(n + 3) + 1
= (n² + n)(n² + 5n + 6) + 1
= n⁴ + 5n³ + 6n² + n³ + 5n² + 6n + 1
= n⁴ + 6n³ + 11n² + 6n + 1
P = (n² + 3n + 1)²
So, P is always perfect square.
∴ (c) is the correct option.