Solution:In ∆ABC,
AB AC = i.e. ∆ABC is isosceles triangle. If L is the locus of points X inside or on the triangle, such that BX CX = . Then, L is a straight line passing through A. As, AX is bisecting the line BC, then it passes through the centroid.
As, AB AC = in ∆ABC, then AX is perpendicular to BC, hence it passes through the orthocentre.
In ∆ABC, AB AC = and AX BC ⊥ . So, AX is angle bisector of ∠A, hence it passes through the incentre. Hence, all statements are correct.