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Trigonometry (Part-6)
📆 July 17, 2025
Total Questions: 50
21.
cos⁴A - sin⁴A is equal to :
[SSC CHSL 03/08/2023 (3rd Shift)]
(a) 2 cos²A + 1
(b) 1 - 2 sin²A
(c) 2 sin²A - 1
(d) -(2sin²A + 1)
Correct Answer:
(b) 1 - 2 sin²A
Solution:
22.
Solve it-
[SSC CHSL 03/08/2023 (4th Shift)]
(a) 49/484
(b) 357/484
(c) 225/484
(d) 7/22
Correct Answer:
(b) 357/484
Solution:
23.
What is the value of the expression.
[SSC CHSL 04/08/2023 (4th Shift)]
(a) secA + cosecA
(b) sinA + cosA
(c) sinA - cosA
(d) secA - cosecA
Correct Answer:
(a) secA + cosecA
Solution:
24.
Simplify the expression.
[SSC CHSL 04/08/2023 (4th Shift)]
(a) 1
(b) 0
(c) -1
(d) 2
Correct Answer:
(a) 1
Solution:
25.
If secθ + tanθ = √3, then the possitive value of sinθ + cosθ is :
[SSC CHSL 04/08/2023 (3rd Shift)]
(a)
(b)
(c)
(d)
Correct Answer:
(a)
Solution:
26.
If 2Tan²A + 4Cos⁴A = 3, then the possible value of A is :
[SSC CHSL 04/08/2023 (4th Shift)]
(a) 45º
(b) 60º
(c) 0º
(d) 30º
Correct Answer:
(a) 45º
Solution:
27.
If a = cotA + cosA and b = cotA - cosA, then find the value of a² - b² - 4 √ab.
[SSC CHSL 04/08/2023 (4th Shift)]
(a) 0
(b) -1
(c) 1
(d) -4
Correct Answer:
(a) 0
Solution:
28.
The given expression is equal to:
[SSC CHSL 07/08/2023 (1st Shift)]
(a) sin²Φ cos²Φ
(b) sin²Φ cot²Φ
(c) cot²Φ cos²Φ
(d) tan²Φ cos²Φ
Correct Answer:
(b) sin²Φ cot²Φ
Solution:
29.
Find the value of cot²B - cosec²B for 0 < B <90º.
[SSC CHSL 07/08/2023 (1st Shift)]
(a) 1
(b) 2
(c) -1
(d) -2
Correct Answer:
(c) -1
Solution:
1 + cot²B = cosec²B
cot²B - cosec²B = -1
30.
In ΔOPQ, right-angled at P, OP = 7 cm and OQ - PQ = 1cm. Determine the values of sin Q + cos Q .
[SSC CHSL 07/08/2023 (2nd Shift)]
(a) 13/25
(b) 21/25
(c) 31/25
(d) 33/25
Correct Answer:
(c) 31/25
Solution:
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