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Trigonometry (Part-6)
📆 July 17, 2025
Total Questions: 50
41.
Find the value of-
[SSC CHSL 08/08/2023 (3rd Shift)]
(a) 1 + 2secA
(b) 2 - secA
(c) 2 + secA
(d) 2 (1 + secA)
Correct Answer:
(d) 2 (1 + secA)
Solution:
42.
If secθ + tanθ = 1/√3, then the possitive value of cotθ + cosθ is :
[SSC CHSL 08/08/2023 (4th Shift)]
(a)
(b)
(c)
(d)
Correct Answer:
(a)
Solution:
43.
Simplify
[SSC CHSL 09/08/2023 (1st Shift)]
(a) 16/25
(b) 40/41
(c) 41/40
(d) 31/30
Correct Answer:
(c) 41/40
Solution:
44.
ΔPQR is right angled at Q. If PQ = 12 cm PR = 13cm, find tan P + cot R.
[SSC CHSL 09/08/2023 (1st Shift)]
(a) 9/10
(b) 0
(c) 10/12
(d) 12/10
Correct Answer:
(c) 10/12
Solution:
45.
If tan A = 1/2 and tan B = 1/3, then the value of A+B is:
[SSC CHSL 09/08/2023 (1st Shift)]
(a) 60º
(b) 15º
(c) 30º
(d) 45º
Correct Answer:
(d) 45º
Solution:
46.
If cotA = 5/12, find the the value of the following expression.
[SSC CHSL 09/08/2023 (2nd Shift)]
(a) 144/5
(b) 24/25
(c) 144/25
(d) 24/5
Correct Answer:
(d) 24/5
Solution:
47.
If tanθ.tan2θ = 1 then the value of cot5θ is:
[SSC CHSL 09/08/2023 (4th Shift)]
(a) -1
(b) 1
(c) -√3
(d) √3
Correct Answer:
(c) -√3
Solution:
48.
If 4 sin²A -3 = 0 and 0 ≤ A ≤ 90º, then 3 sinA - 4sin³A is:
[SSC CHSL 10/08/2023 (1st Shift)]
(a)
(b)
(c)
(d)
Correct Answer:
(c)
Solution:
49.
ΔRMS is right-angled at M. The length of the base, RM = 4cm and the length of perpandicular MS = 3cm. Find the value of sec R.
[SSC CHSL 10/08/2023 (3rd Shift)]
(a) 3/4
(b) 5/4
(c) 4/5
(d) 2/5
Correct Answer:
(b) 5/4
Solution:
50.
Find the value of the following expression.
[SSC CHSL 10/08/2023 (4th Shift)]
2(tan²A cos²A + cos²A)
(a) 4
(b) 1
(c) 3
(d) 2
Correct Answer:
(d) 2
Solution:
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