Trigonometry (Part-6)Total Questions: 5041. Find the value of- [SSC CHSL 08/08/2023 (3rd Shift)](a) 1 + 2secA(b) 2 - secA(c) 2 + secA(d) 2 (1 + secA)Correct Answer: (d) 2 (1 + secA)Solution:42. If secθ + tanθ = 1/√3, then the possitive value of cotθ + cosθ is : [SSC CHSL 08/08/2023 (4th Shift)](a)(b)(c)(d)Correct Answer: (a)Solution:43. Simplify [SSC CHSL 09/08/2023 (1st Shift)](a) 16/25(b) 40/41(c) 41/40(d) 31/30Correct Answer: (c) 41/40Solution:44. ΔPQR is right angled at Q. If PQ = 12 cm PR = 13cm, find tan P + cot R. [SSC CHSL 09/08/2023 (1st Shift)](a) 9/10(b) 0(c) 10/12(d) 12/10Correct Answer: (c) 10/12Solution:45. If tan A = 1/2 and tan B = 1/3, then the value of A+B is: [SSC CHSL 09/08/2023 (1st Shift)](a) 60º(b) 15º(c) 30º(d) 45ºCorrect Answer: (d) 45ºSolution:46. If cotA = 5/12, find the the value of the following expression. [SSC CHSL 09/08/2023 (2nd Shift)](a) 144/5(b) 24/25(c) 144/25(d) 24/5Correct Answer: (d) 24/5Solution:47. If tanθ.tan2θ = 1 then the value of cot5θ is: [SSC CHSL 09/08/2023 (4th Shift)](a) -1(b) 1(c) -√3(d) √3Correct Answer: (c) -√3Solution:48. If 4 sin²A -3 = 0 and 0 ≤ A ≤ 90º, then 3 sinA - 4sin³A is: [SSC CHSL 10/08/2023 (1st Shift)](a)(b)(c)(d)Correct Answer: (c)Solution:49. ΔRMS is right-angled at M. The length of the base, RM = 4cm and the length of perpandicular MS = 3cm. Find the value of sec R. [SSC CHSL 10/08/2023 (3rd Shift)](a) 3/4(b) 5/4(c) 4/5(d) 2/5Correct Answer: (b) 5/4Solution:50. Find the value of the following expression. [SSC CHSL 10/08/2023 (4th Shift)]2(tan²A cos²A + cos²A)(a) 4(b) 1(c) 3(d) 2Correct Answer: (d) 2Solution:Submit Quiz« Previous12345