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Trigonometry (Part-7)
📆 July 21, 2025
Total Questions: 50
1.
If A,B,C are the acute angles, such than tan (A + B - C) = 1/√3, cos (B + C - A) = 1/2 and sin (C + A - B) = 1/√2. The value of A + B +C will be equal to:
[SSC CHSL 10/8/2023 (4th Shift)]
(a) 90º
(b) 110º
(c) 170º
(d) 135º
Correct Answer:
(d) 135º
Solution:
2.
Find the value of the following expression.
[SSC CHSL 10/08/2023 (4th Shift)]
(a) cos²Ø
(b) sec²Ø
(c) cot²Ø
(d) sin²Ø
Correct Answer:
(d) sin²Ø
Solution:
3.
Let ABC be a right-angled triangle where ∠A = 90º and ∠C = 45º. Find the value of secC + sinC + secC.
[SSC CHSL 11/08/2023 (1st Shift)]
(a) 1
(b) 1 - √2
(c) 1 + √2
(d) √2 - 1
Correct Answer:
(c) 1 + √2
Solution:
4.
If (4 sinθ + 5 cosθ) = 3, then the value of (4 cosθ - 5 sinθ) is:
[SSC CHSL 11/08/2023 (1st Shift)]
(a) 3√2
(b) 4√2
(c) 2√3
(d) 2√5
Correct Answer:
(b) 4√2
Solution:
5.
Let ABC be a triangle right-angled at B. If tan A = 12/5, then find the values of cosecA and secA, respectively.
[SSC CHSL 11/08/2023 (3rd Shift)]
(a)
(b)
(c)
(d)
Correct Answer:
(b)
Solution:
6.
If cosθ - sinθ = 0, then (sin⁸θ + cos⁸θ) is:
[SSC CHSL 11/08/2023 (3rd Shift)]
(a) 1/8
(b) 1/4
(c) 1/6
(d) 1/2
Correct Answer:
(a) 1/8
Solution:
7.
Simplify the given expression.
[SSC CHSL 11/08/2023 (4th Shift)]
(a) 9
(b) 2
(c) 4
(d) 6
Correct Answer:
(d) 6
Solution:
8.
Find the value of Sin47º Cos33º - Cos43º Sin57º.
[SSC CHSL 14/08/2023 (2nd Shift)]
(a) -1
(b) 1
(c) 0
(d) 1/2
Correct Answer:
(c) 0
Solution:
9.
The value of-
[SSC CHSL 14/08/2023 (3rd Shift)]
(a) 2 secA
(b) 2 cosecA
(c) secA
(d) cosecA
Correct Answer:
(a) 2 secA
Solution:
10.
Simplify the given expression. (1 + tan²A) (1 + cot²A) = ?
[SSC CHSL 14/08/2023 (3rd Shift)]
(a)
(b)
(c)
(d)
Correct Answer:
(b)
Solution:
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