Trigonometry (Part-7)Total Questions: 5011. The given expression is equal to: [SSC CHSL 14/08/2023 (4th Shift)](cotB - tanB). sinB. cosB(a) 1 - 2sec²B(c) 2 cos²B(b) 1 - 2cos²B(d) 2 sec²B - 1Correct Answer: (c) 2 cos²BSolution:12. cot²θ - cosec²θ equals to: [SSC CHSL 17/08/2023 (1st Shift)](a) 0(b) tanθ(c) 1(d) -1Correct Answer: (d) -1Solution:13. If sinθ cosθ = 1/√3 then then value of (sin⁴θ +cos⁴θ) is: [SSC CHSL 17/08/2023 (3rd Shift)](a) 1(b) 5/3(c) 2/3(d) 1/3Correct Answer: (d) 1/3Solution:14. Simplify the given expression. [SSC CHSL 17/08/2023 (3rd Shift)](a) cosec P - cot P(b) sec P - tan P(c) sec P + tan P(d) cosec P + cot PCorrect Answer: (d) cosec P + cot PSolution:15. Find the value of tan (50 + θ) - Cot (40 - θ). [SSC CHSL 17/08/2023 (4th Shift)](a) 1/2(b) -1(c) 0(d) 1Correct Answer: (c) 0Solution:16. What is the value of (1 - sin²A) cosec²A? [SSC CHSL 17/08/2023 (4th Shift)]Given A is an acute angle.(a) cot²A(b) cos²A(c) tan²A(d) sin²ACorrect Answer: (a) cot²ASolution:17. If Tan15º = 2 - √3, then the value of Tan15º Cot75º + Tan75º Cot15º is: [SSC CHSL 17/08/2023 (4th Shift)](a) 6(b) 10(c) 8(d) 14Correct Answer: (d) 14Solution:18. Simplify [SSC CGL 14/07/2023 (1st Shift)](a) 3(b) 0(c) 1(d) 2Correct Answer: (c) 1Solution:19. Evaluate the following: [SSC CGL 14/07/2023 (2nd Shift)]cos (36º + A). cos(36º - A) + cos(54º + A). cos(54º - A)(a) sin2A(b) cosA(c) sinA(d) cos2ACorrect Answer: (d) cos2ASolution:20. If sin 23º = a/b, then the value of sec23º - sin67º is_______ . [SSC CGL 14/07/2023 (3rd Shift)](a)(b)(c)(d)Correct Answer: (d)Solution:Submit Quiz« Previous12345Next »