U.G.C. NET Exam. December 2022 Paper II (COMPUTER SCIENCE) And Applicatation.

91. An organization is granted the block 130.56.0.0/16. The administrator wants to create 1024 subnets. Find the number of addresses in each subnet

(a) 32
(b) 64
(c) 128
(d) 16

Correct Answer: (b) 64

Solution:

92. An organization is granted the block 130.56.0.0/16. The administrator wants to create 1024 subnets. Find the subnet prefix.

(a) 130.56
(b) 136.0
(c) 136.255
(d) 136.56.255

Correct Answer: (a) 130.56

Solution:

93. An organization is granted the block 130.56.0.0/16. The administrator wants to create 1024 subnets. Find first and last addresses of First subnet.

Correct Answer: (b)

Solution:

The first address is subnet 1 = 130.56.0.1 The last address is subnet 1 = 130.560.62 the first address of is the address 130.56.00 and subnet mask/26 connected by AND, and next can be estimated as 10000010 00000010.0.0
This address cannot be assigned, so consider the following 10000010 00111000 00000000 00000001(130.56.0.1
Similarly to the last address that can be assigned before the broadcast address is 130.56.0.62.

94. An organization is granted the block 130.56.0.0/16. The administrator wants to create 1024 subnets. Find first and last addresses of last subnet.

Correct Answer: (e) *

Solution:

First address in 1024 subnet = 130.56.255.193 1024 last address in subnet = 130.56.255.254 this is total number of addresses.

95. An organization is granted the block 130.56.0.0/16. The administrator wants to create 1024 subnets. Find subnet mask.

Correct Answer: (e) *

Solution:

2ⁿ = 1024
So n = 10
Address is class B, so the default mask for it / 16. Since subnet and require 10 bits the correct subnet mask is / (16 + 10) = /26. The subnet mask is 255.255.255.192 because it is 192 in decimal format with dots.