U.G.C. NET Exam. December 2023 Paper II (COMPUTER SCIENCE)

Total Questions: 100

31. The sum of minimum and maximum number of final states for a Deterministic Finite Automata (DFA) having 'P' state is equal to:

Correct Answer: (c) p + 1
Solution:

The maximum number of final states for a DFA can be total number of states itself and minimum would always be 1, as no DFA exists without a final state. Therefore, Then sum of minimum and maximum number

32. Test suite is consist of :

Correct Answer: (c) Set of test cases
Solution:

Test suite is a container that has a set of tests which helps testers in executing and reporting the test execution status. It can take any of the three states namely Active, Inprogress and completed, A Test case can be added to multiple test suites and test plans. After creating a test plan , test suites are created which in turn can have any number of tests. Test suits are created based on the cycle or based or the scope. It can contain any type of tests, functional or Non- functional.

33. A multiplexes combines for 100 Kbps channels using a time slot of 2 bits. What is the bit rate?

Correct Answer: (e) *
Solution:

A time division multiplexing system Combines multiple channels by interleaving bits by time. The bit rate of the multiplexed channel is determined by The number of time slots and the bit rate of the individual channels.
If we combine four 100 kbps channels using a time slot of 2 bits, the bit rate of the multiplexed channel can be calculated as follows. Bit Rate = FrameRate ×Number of Bits per frame = 50000 frames/see× 8 bits/frame = 400 kbps So the correct option is = 400 kbps.

34. Which of the following is not a field in TCP header?

Correct Answer: (d) Window size
Solution:

Fragmentation offset is a field in the IP header, not in the TCP header. In the TCP header, the fields are sequence Number, checksum, and window size, among others, but not fragmentation offset. TCP operates at the transport layer, while fragmentation occurs at the network layer (IP layer), where packets are divided into smaller fragments to fit into the maximum transmission unit (MTU) of the network.

35. In "bit stuffing", each frame begins and ends with a bit pattern in hexadecimal?

Correct Answer: (d) Ox7E
Solution:

In bit stuffing, each frame typically begins and ends with a specific bit pattern, not necessarily in hexadecimal. The purpose of this pattern is to enable the receiver to identify the start and end of the frame. In some networking protocols, Such as HDLC (HighLevel Data Link Control), each frame begins and ends with a special bit pattern, 01111110 or 0 × 7E in hexadecimal. This pattern is a flag byte.

36. Level - 0 DFD is also called as:

Correct Answer: (c) Context Diagram
Solution:

In software engineering DFD (Data Flow Diagram) can be drawn to represents the system of different levels of abstruction. DFD level - 0 is also called a context Diagram. It is a basic overview of the whole system or process being analyzed or modeled. It is designed to be an at-glance view, showing the system as a single high-level process, with its relationship to external entities.

37. What is the generic structure of Multi Agent System (MAS)?

Correct Answer: (c) Multiagents with diverse objectives and communication abilities
Solution:

The generic structure of a multi Agent system (MAS) typically involves multiagents with diverse objectives and communication, abilities. This structure allows for interaction between multiple agents with varying goals and the capability to communicate and collaborate to achieve those objectives.

38. A_______ point of fuzzy set A is a point x∈X at which µA (x) = 0.5

Correct Answer: (c) Crossover
Solution:

A crossover point of fuzzy set A is a point x∈x at which µA(x) = 0.5. This point represents the boundary where an element is equally likely to be inside or outside of the fuzzy set A.

39. In a genetic algorithm optimization problem the fitness function is defined as f(x) = x² – 4x + 4. Given a population of four individuals with values of x : {1.5, 2.0, 3.0, 4.5} What is the fitness value of the individual that will be selected as the parent for reproduction in one generation?

Correct Answer: (d) 6.25
Solution:

To find the fitness value of each individual in the population, we plug in the given values of x into the fitness function f(x) = x² – 4x + 4.
Given a population of four individuals with values of
x : {1.5, 2.0, 3.0, 4.5}
for x = 1.5
f(1.5) = (1.5)² – 4(1.5) + 4 = 0.25
for x = 2.0
f (2.0) = (2.0)² – 4 (2.0) + 4 = 0
for x = 3.0
f(3.0) = (3.0)² – 4(3.0) + 4 =1
for x = 4.5
f (4.5) = (4.5)² – 4 (4.5) + 4 = 6.25
The individual with x = 4.5 has the highest fitness value of 6.25 and would likely be selected as the parent for reproduction in one generation.

40. In a feed forward neural network with the following specifications:

Correct Answer: (a) [0.62, 0.68]
Solution:

The proceed with the calculations-