UGC NTA NET/JRF Exam, Environmental Sciences, June-2025

Total Questions: 99

11. Arrange the following unit processes of sludge treatment from first to the last:

A. Stabilization
B. Dewatering
C. Conditioning
D. Thickening
E. Reduction
Choose the correct answer from the options given below:

Correct Answer: 4. D, A, C, B, Е
Solution:

D.Thickening → first: Raw sludge is very dilute (≈0.5-2% solids). Gravity/thickening reduces volume early to lower sizing/energy needs downstream.

A. Stabilization → second: Anaerobic/aerobic digestion (or lime stabilization) reduces volatile solids, pathogens, odors, and biogas may be produced. Stabilizing before mechanical handling improves safety and dewatering behavior.

C. Conditioning → third: Chemical (polymers, ferric, lime) or thermal conditioning added immediately before dewatering to improve floc structure, drainage, and cake solids.

B. Dewatering → fourth: Centrifuges, belt presses, filter presses remove free/interstitial water to produce a stackable "cake" (typically 15-35% TS depending on process).

E. Reduction → last: Further volume/ mass reduction and final treatment (e.g., drying beds, thermal drying, composting, incineration) or beneficial use/disposal.

12. Consider the following are statements regarding visualization methods for describing data.

A. We can calculate value of 55th percentile from Box-plots.
B. Chernoff plot is a Hierarchical chart.
C. In Pie-chart, area of circle is nonproportional to frequency of a particular categorical response.
D. Ishikawa diagrams are used for visualizing the cause and effect relationship.
E. Histogram is used for categorical data.
Choose the correct answer from the options given below:

Correct Answer: 5. (*)
Solution:

А. Воx-plot gives 55th percentile: Incorrect. Standard box-plots display median (50th), Q1 (25th), Q3 (75th), whiskers, and outliers; they do not yield the 55th percentile exactly.

B. Chernoff plot is hierarchical: Incorrect. Chernoff faces encode multivariate variables as facial features; they are not a hierarchical chart.

C. Pie-chart: area of circle non-proportional to frequency: Incorrect/misleading. In pie charts, a category's sector (angle/area) is proportional to its frequency; the claim as stated is not correct for how values are represented.

D. Ishikawa for cause-effect: Correct. Ishikawa/ fishbone diagrams visualize cause-effect relationships.

E. Histogram for categorical data: Incorrect. Histograms are for continuous (binned) numerical data; bar charts suit categorical data.

Net: Only D is correct, but no option contains D only ⇒ NONE.

13. Which of the following best explains the rational behind categorizing projects as Category A and Category B in the EIA Notification of 2006?

Correct Answer: 2. To delegate simpler projects to state authorities and complex ones to the central government.
Solution:

To delegate simpler projects to state authorities and complex ones to the central government.

Rationale in EIA 2006: Projects are categorized by scale and potential environmental impact.

Category A: Appraised at Central (MoEFCC/ EAC) due to larger scale/significant impacts, mandatory EIA and often public hearing.

Category B: Handled by State (SEIAA/ SEAC); B1 typically requires EIA, B2 may be exempt from full EIA.

This structure allocates appraisal to the appropriate level and streamlines the process while maintaining rigor for higher-impact projects.

14. Match the LIST-I with LIST-II.

LIST-I (Article)LIST-II (Description)
A. 51A(g)I. Protection of monuments and places and objects of national importance
B. 49II. To protect and improve the national environment including forest, lakes, rivers and wildlife, and to have compassion for living creatures
C. 48III. Protection and improvement of environment and safeguarding of forest and wildlife
D. 48AIV. Organization of agriculture and animal husbandry

Choose the correct answer from the options given below:

Correct Answer: 3. A-II, B-I, C-IV, D-III
Solution:

A. Article 51A(g) → II: Fundamental Duty "to protect and improve the natural environment (forests, lakes, rivers, wildlife) and to have compassion for living creatures."

B. Article 49 → I: Protection of monuments and places and objects of national importance.

C. Article 48 → IV: Organization of agriculture and animal husbandry on modern/scientific lines (incl. breed improvement, cow protection).

D. Article 48A → III: Protection and improvement of environment and safeguarding of forests and wildlife (42nd Amendment, 1976).

Mapping: 51A(g)-II; 49-I; 48-IV; 48A-III ⇒ A-II, B-I, C-IV, D-III.

15. The proportion of the assimilated food that is used to produce new consumer biomass is production efficiency.

Arrange the following ectothermic organisms in the increasing order of their production efficiency.
A. Fishes
B. Carnivores
C. Herbivores
D. Detritivores
Choose the correct answer from the options given below:

Correct Answer: 2. A, C, D, B
Solution:

Concept: Production efficiency = fraction of assimilated energy converted to new consumer biomass. It rises with food quality and lower metabolic overhead; ectotherms generally exceed endotherms.

D. Detritivores lowest: Detritus is lowquality, refractory (high lignin/cellulose), with microbial defenses; even after assimilation, a larger share goes to maintenance, so lower production efficiency.

A. Fishes → next: Ectothermic and buoyant (favorable vs. terrestrial vertebrates) but as vertebrates they still have higher maintenance costs than many invertebrates; moderate production efficiency.

C. Herbivores → higher: Many ectothermic herbivores (e.g., insects) can achieve high conversion of assimilates due to efficient growth strategies.

B. Carnivores → highest: Protein-rich, easily digestible prey yields high assimilation; with ectothermic metabolism, a greater fraction of assimilates is converted to biomass.

Order (increasing): Detritivores < Fishes < Herbivores < Carnivores = D, A, С, В.

16. Consider the following statements and choose the INCORRECT statement.

Correct Answer: 2. More ozone will be formed in an area having high NO compared to NO₂ concentration in ambient atmosphere.
Solution:

Statement 2 is incorrect. Ground-level ozone (O₃) production depends on NO₂ photolysis and VOC radicals. Where NO is high, it titrates ozone via NO + O₃→ NO₂ + O₂, thereby reducing O₃ even if NOx is abundant.

1 (Correct): Diesel engines operate lean; the globally cooler, oxygen-rich bulk mix can yield lower thermal NO formation compared with stoichiometric gasoline flame cores (engine-out NO chemistry is nuanced, but the lean regime tends to suppress peak NO in bulk).

3 (Correct): London (1952) smog was a sulfurous/reducing smog driven by SO₂ and smoke; ozone was not the dominant oxidant species.

4 (Correct): Aldehydes (carbonyls) have n → π* bands in near-UV; they absorb strongly in UV-B (<315 nm) with weak tails into short-wavelength UV-A for several species.

17. Arrange the following states of India in the order of their ranking (top to bottom) in Swachh Survekshan 2023.

A. Chattisgarh
B. Madhya Pradesh
C. Maharashtra
D. Odisha
E. Telangana
Choose the correct answer from the options given below:

Correct Answer: 3. C, B, A, D, E
Solution:

С. Maharashtra: In Swachh Survekshan 2023, Maharashtra ranked as the best-performing state in cleanliness among large states. Its strong solid waste management systems, decentralized waste segregation, and largescale citizen participation initiatives pushed it to the top.

B. Madhya Pradesh: Secured the second position. Cities like Indore (ranked India's cleanest city for the 7th consecutive year) contributed heavily to this ranking.

A. Chhattisgarh: Took the third place. It has consistently been among the top states due to strong community-level waste segregation and urban cleanliness drives.

D. Odisha: Ranked lower than the above three, but still ahead of Telangana due to improvements in waste processing facilities.

E. Telangana: Placed the lowest among the listed states, reflecting ongoing challenges in scaling up urban sanitation infrastructure.

Order (Top → Bottom): Maharashtra → Madhya Pradesh → Chhattisgarh → Odisha → Telangana.

18. Which of the following is NOT true for ecological succession?

Correct Answer: 4. Colonizing species face less competition for resources in secondary succession compared to primary succession.
Solution:

Colonizing species face less competition for resources in secondary succession compared to primary succession:

Primary succession: Begins on new, barren substrates (e.g., bare rock, lava, sand dunes). Colonizers (lichens, mosses) face harsh abiotic stress like no soil, limited water/nutrients, temperature extremes. However, because very few organisms are present, competition is initially low.

Secondary succession: Occurs after disturbance (e.g., fire, flood, agriculture). Since soil, seed banks, roots, and microbes remain, many species can re-colonize quickly.

This results in higher initial competition among species for nutrients, light, and space.

Thus, statement 4 is incorrect, because competition is generally stronger in secondary succession than in primary succession.

19. Choose the correct mathematical expressions related to noise.


Choose the correct answer from the options given below:

Correct Answer: 3. A, B, Dand E only
Solution:

A. Sound power (W) = Intensity (I) Area (A): Correct. Power is the total sound energy per second crossing a surface area at a given intensity.

B. Sound period (T) and frequency (f) are inversely related: Correct since T = 1/f.

C. Speed of sound formula given (C = 20.05 × Temp²): Incorrect. The speed of sound is proportional to the square root of absolute temperature, not quadratic. Correct relation: c= √YRT or approximately c = 331 + 0.6T(°C).

D. L = 10 log₁₀(Q/Q₀): Correct formula for expressing sound levels (e.g., power level, intensity level) in decibels relative to a reference.

E. I = P²ms /(pc): Correct relation connecting sound intensity with root-mean-square acoustic pressure in a plane progressive wave.
Hence, the valid set is A, B, D, E.

20. What will be the aerodynamic diameter of a spherical particle having diameter of 2 µm and density of 3 g/cm³? Terminal velocity of spherical particle and the reference particle are same and the density of reference particle is 1 g/cm³.

Correct Answer: 2.~ 3.5 µm
Solution:

The aerodynamic diameter (d) represents the size of a unit-density sphere (1 g/cm³) with the same settling velocity as the particle.
Formula:
Rounded to one decimal: ≈ 3.5 µm.
Thus, the aerodynamic diameter of the given particle is about 3.5 µm.