UGC NTA NET/JRF Exam, Environmental Sciences, June-2025

Total Questions: 99

41. Arrange the following steps of an idealized EIA process in order of execution:

A. Assessment
B. Audit
C. Decision Making
D. Evaluation
E. Mitigation
Choose the correct answer from the options given below:

Correct Answer: 1. A, D, E, С, B
Solution:

A. Assessment → Identify baseline conditions; predict project-induced impacts on environmental receptors.

D. Evaluation → Judge the significance of predicted impacts (magnitude, duration, reversibility, sensitivity of receptors); weigh alternatives.

E. Mitigation → Design and commit to avoidance, minimization, restoration, and offset measures; integrate into the EMP/ EMC.

C. Decision Making→ Competent authority issues approval/conditions/rejection based on the EIA/EMP, public hearing, and appraisal.

B. Audit → Post-project environmental audit/ monitoring & feedback: verify predictions, check compliance and effectiveness of mitigation, and feed learning into future EIAs.

42. Which of the following is INCORRECT about nuclear power plants used for energy generation?

Correct Answer: 2. Control rods in fission reactors are made from Graphite, neutron absorbing element.
Solution:

Incorrect statement: "Control rods in fission reactors are made from graphite, neutron absorbing element."

Why: Control rods are made of strong neutron absorbers like boron, cadmium, hafnium, AgIn-Cd alloys. Graphite is a moderator (slows neutrons) not a control-rod absorber. Checks on other items:

1 (True): Naturally occurring fissile uranium isotope is U-235 (U-238 and Th-232 are fertile, not fissile).

3 (True): Breeder reactors produce more fissile fuel (e.g., Pu-239 or U-233) than they consume.

4 (True): Thermal thorium breeder converts Th-232→ U-233 via neutron capture and beta decays.

43. In an aquatic system, high consumption rates (herbivores) and relatively short life spans of the primary producers (phytoplankton) result in a inverted pyramid of biomass relative to pyramid of energy. Which of the following are correct?

A. Biomass of heterotrophs is greater at any given time than biomass of the autotrophs.
B. Energy produced by autotrophs is greater than that produced by heterotrophs.
C. Inverted pyramid of biomass are most common in nutrient poor water with low autotroph biomass.
D. Detritus makes lower proportional contribution to energy flow in nutrient poor water than in nutrient rich water.
E. Biomass ratio (heterotrophs/autotrophs) of above one indicate inverted pyramid.
Choose the correct answer from the options given below: 

Correct Answer: 2. A, B, C and E only
Solution:

Context: In many aquatic systems, phytoplankton have short lifespans and are heavily grazed; consumer biomass can exceed standing producer biomass, yielding an inverted biomass pyramid, even though energy pyramids always taper with trophic level.

A. (True): At any instant, heterotroph biomass can be greater than autotroph biomass (the hallmark of an inverted biomass pyramid).

B. (True): Energy produced by autotrophs (GPP/ NPP) still exceeds that passed to heterotrophs; energy pyramids are never inverted.

C. (True): Inversions are common in open, nutrient-poor waters with low producer standing stock and high turnover under strong grazing.

D. (Not selected): The detrital/microbial loop can be important even in oligotrophic systems; it is not generally correct to assert a lower proportional detrital contribution there relative to eutrophic waters.

E. (True): Heterotrophs/autotrophs biomass ratio > 1 indicates an inverted biomass pyramid.

44. Arrange the following statements regarding calculations of Chi-square test statistic for assessing association between two categorical variables in the correct sequence.

A. Calculate value of 𝒳² statistic.
B. Calculate expected cell frequencies.
C. Assess degree of freedom.
D. Tabulate data in contingency table.
E. Compare calculated value with critical value and take decision.
Choose the correct answer from the options given below:

Correct Answer: 4. D, B, A, C, Е
Solution:

45. Choose the CORRECT statements about air pollution control methods.

A. Impaction of particles is directly proportional to particle density and diameter squared.
B. Probability of resuspension of particles is inversely proportional to particle diameter.
C. In cyclones, force produced by rotational motion of fluid is directly proportional to square of terminal velocity.
D. Activated alumina and sulfuric acid are common water vapour collection materials used in demisters.
E. Baghouses dust collector does not work on the principle of sedimentation and electrostatic attraction of particles.
Choose the correct answer from the options given below:

Correct Answer: 1. A, B, C and D only
Solution:

A. - Correct. Impaction α Pᴘ. dᴘ² Inertial impaction efficiency rises with particle inertia. The Stokes number for impaction scales as Stkd α Pᴘdᴘ² (for fixed flow/ geometry), so higher particle density and diameter squared increase capture in devices (baffles, cyclones, mesh pads).

B. Resuspension vs size - Correct (exam convention). For typical dusts in air-pollution control (≈1- 100 µm), smaller deposited particles are more easily re-entrained under the same shear because aerodynamic lift/drag scale less steeply with size than weight; thus a common engineering rule is resuspension probability increases as particle size decreases (i.e., inversely with dᴘ).

(Very fine cohesive powders can be an exception, but the standard MCQ generalization treats the trend as inverse.)

C. Cyclones: force α velocity² - Correct (intended sense). Separation is driven by centrifugal force F🇨 = mv²lr, i.e., proportional to the square of the tangential velocity.

Design relations often connect cut-size to the particle's terminal settling characteristics, but the governing inertial term is the v² dependence captured in the statement.

D. "Activated alumina & H₂SO₄ used in demisters" - Incorrect. Demisters (mist eliminators) remove liquid droplets mechanically (impaction/ interception/centrifuging) using mesh or vane packs.

Activated alumina (adsorbent) and concentrated sulfuric acid (desiccant) are gas-drying media used in dryers/sampling trains-not the collection media in demisters.

E. Baghouses do not operate by sedimentation or electrostatics - Correct. Fabric filters capture particles by depth/ surface filtration (interception, impaction, diffusion, and cake sieving).

They do not rely on gravitational settling (settling chambers) or electrostatic attraction (ESPs). Any fiber charge is incidental; the principle is mechanical filtration.

46. Arrange the following terrestrial biomes in the decreasing order of their global average Net Primary Productivity (g/m²/yr).

A. Boreal Forest
B. Temperate Grassland
C. Tropical Forest
D. Temperate forest
E. Crops
Choose the correct answer from the options given below:

Correct Answer: 1. C, D, E, B, A
Solution:

C. Tropical forest - highest NPP: Warm year-round temperatures, high rainfall, intense insolation, and continuous growing seasons drive very high net primary productivity (typically ~1800-2500 g m⁻² yr⁻¹). Dense, multi-layered canopies and rapid nutrient cycling keep photosynthesis high nearly all year.

D. Temperate forest: Marked seasons but long enough growing periods, moderate temperatures, and adequate moisture support high NPP (about ~800-1400 g m⁻² yr⁻¹). Deciduous and mixed forests maintain substantial leaf area during the growing season, elevating carbon gain.

E. Crops: Although highly variable by crop typе and management, managed agro-ecosystems (fertilizers, irrigation, high-yield varieties, weed/pest control) often achieve moderate10-high NPP on a per-area basis (roughly - 500-1100 g m⁻² yr⁻¹ y on global averages), commonly exceeding many natural grasslands.

B.  Temperate grassland: Productivity is limited by seasonal water stress, periodic droughts, and strong herbivory/fire regimes; typical NPP ~400-800 m⁻² yr⁻.

While peak growth can be vigorous, shorter favorable windows and moisture constraints keep annual totals below most forests and well-managed crops.

A. Boreal forest - lowest among the five (on average): Cold climates, short growing seasons, low sun angles, nutrient-poor acidic soils, and, in places, permafrost depress photosynthesis and decomposition, yielding lower NPP (often ~300-700 g m⁻² yr⁻) than temperate systems and most croplands.

Decreasing order (global averages): Tropical forest > Temperate forest > Crops : Temperate grassland > Boreal forest, i.e., C, D, E, B, А.

47. Match the LIST-I with LIST-II.

LIST-I (Lapse rate condition)LIST-II (Stability class)
A. γ<γsI. Absolutely Unstable
B. γ>γdII. Conditionally Unstable
C. γ=γdIII. Absolutely Stable
D. γs>γ>γdIV. Dry Neutral

Choose the correct answer from the options given below:

Correct Answer: 3. A-III, B-I, C-IV, D-II
Solution:

48. The solid organic fraction of______are mainly derived from lower plants lacking lignocellulosic tissues.

Correct Answer: 2. Bituminous shales
Solution:

The solid organic fraction (kerogen) in bituminous (oil) shales is predominantly derived from lower plants/algae lacking lignocellulosic tissues. In contrast, lignite, bituminous coal, anthracite originate mainly from higher land plants rich in lignocellulose, altered through diagenesis and coalification.

49. Which of the following is NOT true for composting of waste?

Correct Answer: 1. Moisture should not be present.
Solution:

Incorrect statement: Composting is a biological, aerobic process requiring adequate moisture, typically~50-60% (wet basis) for microbial activity and heat transfer. Saying moisture "should not be present" is wrong.
Correct practices:
Particle size <~5 cm: Promotes aeration and surface area for microbes. Compost improves soil water-holding capacity: Humified organics enhance aggregation and porosity.
C:N~20-25:1 (often 25-30:1 optimal): Ensures balanced microbial growth and efficient decomposition.

50. In an open system, which of the following does not partition between the gas and aqueous phase?

Correct Answer: 3. H₃PO₄
Solution: