Solution:Given , that total number of students were 110. And 23 students did not participate in any game.So, remaining students. (110 - 23) = 87 Only badminton playing students is p(b) = 45 Only chess playing students p(a) = 61
We know that ,
p (a∪b)= p(a) + p(b) - p(a∩ b)
87 = 61 + 45 - p (a∪b)
p (a∪b)= 19
So students playing both games are 19. Therefore we can say that the students playing only badminton are = 45 - 19 = 26
