Correct Answer: (b) 10 ohm
Note: we know that
R=(ρ*l)/a
R= resistance
ρ= resistivity
l=length
a=area
let the ρ1,l1 and r1 is resistance length and radius of the first wire respectively then
as per question
resistivity of second wire ρ2=2ρ1
length of the second wire l2=2l1
radius of the second wire r2=2r1
⇒R1=(ρ1*l1)/a1=(ρ1*l1)/πr1²
R2=(ρ2*l2)/a2=(2ρ1*2l1)/π(r1)²
=4(ρ1*l1)/4πr1²=(ρ1*l1)/πr1²
⇒R1/R2=1
Since the resistance of thin wire R1=10Ω
therefore resistance of the thicker wire R2=10Ω