Physics (Part-IV) (Railway)

Total Questions: 50

31. The device that uses ultrasonic waves to measure the distance, direction and speed of underwater objects is called: [RRB NTPC CBT-1 Exam, 01.04.2021 (Shift-I)]

Correct Answer: (1) SONAR
Solution:Sonar, short for Sound Navigation and Ranging.

•  Sonar uses sound propagation to navigate, measure distances. communicate with or detect objects on or under the surface of the water.

32. Who is considered to be the 'father of modern science'? [RRB NTPC CBT-1 Exam, 05.04.2021 (Shift-I)]

Correct Answer: (1) Galileo Galilei
Solution:Galileo Galilei is known as the "father of modern science."

• He was born on February 15, 1564, in Pisa.

• He was an Italian physicist, astronomer, philosopher, and mathematician.

33. Which of the following is NOT based on the Archimedes' Principle? [RRB NTPC CBT-1 Exam, 06.04.2021 (Shift-I)]

Correct Answer: (1) Designing of aeroplane wings
Solution:Designing of aeroplane wings is based on a principle of aerodynamics called Bernoulli's law.

34. Which electric device is NOT base on Joule's law of heating? [RRB NTPC CBT-1 Exam, 06.04.2021 (Shift-I)]

Correct Answer: (4) Electric plugs and switches
Solution:Joule's Law of Heating:- Joule's law is a mathematical expression of the rate at which resistance in a circuit turns electric energy into heat energy.

• Electrical devices like Electric fuse, electric iron, electric toaster, and electric heater are based on the principle of Joules law.

35. Which of the following is an example of scattering of light? [RRB NTPC CBT-1 Exam, 07.04.2021 (Shift-I)]

Correct Answer: (3) Blue colour of the sky
Solution:The blue colour is scattered more and hence the sky appears blue.

• The reason for more scattering of blue colour is that the wavelength of the blue light is shorter than the other light.

• So blue light is scattered in all directions by the tiny molecules of air in Earth's atmosphere.

36. The distance between the focus and the centre of curvature of a spherical mirror in terms of the radius of curvature R, is equal to [RRB Group 'D' CBT Exam, 17.08.2022 (Shift-II)]

Correct Answer: (2) R/2
Solution:Focal length (f) is the distance from mirror at which the light rays coming parallel from infinity meet.

•  Radius of Curvature R is the radius of the sphere of which the mirror is a part.

• Focal length and radius of curvature are related as:f = R/2

37. The armature of an electric motor consists of which of the following part/parts? [RRB Group 'D' CBT Exam, 17.08.2022 (Shift-II)]

(i) Soft iron core

(ii) Coll

(iii) Magnets

Correct Answer: (4) Both (1) and (ii)
Solution:The armature consists of a rectangular coll made of insulated copper wire wound on a soft iron core.

• The coil is mounted on an axIe and is placed between the cylindrical concave poles of a magnet.

• The commutator is used to reverse the direction of flow of current.

38. In accordance to Fleming's left hand rule used to find the force on a current carrying conductor placed inside a magnetic field, the thumb and the index finger represent the directions of __________ and ______ respectively. [RRB Group 'D' CBT Exam, 17.08.2022 (Shift-II)]

Correct Answer: (3) force, magnetic field
Solution:According to Fleming's left-hand rule.

• if we stretch the thumb, forefinger, and the middle finger of the left-hand perpendicular to each other, then the forefinger indicates the direction of the magnetic field, the middle finger denotes the direction of current and the thumb represents the direction of the force.

39. In the figure shown below, the incident ray and the emergent ray in the respective order are given by: [RRB Group 'D' CBT Exam, 17.08.2022 (Shift-II)]

Correct Answer: (1) AB and CD
Solution:

So, from the above diagram it is clear that AB is incident ray and CD is an emergent ray.

40. An object placed at a distance of 25 cm from a converging lens forms a real and inverted image at 30cm from the lens. The magnification produced by the lens is equal to: [RRB Group 'D' CBT Exam, 17.08.2022 (Shift-II)]

Correct Answer: (2)-6/5
Solution:The magnification of a lens is equal to the ratio of image distance to that of object distance.

• In other words, m= v/u, where v is the image distance and u is the object distance

• So, m=30/25 = 6/5

• In convex lens, the real image is inverted hence its magnification is negative.

So, m = - 6/5