Correct Answer: (3) -20cm, virtual and erect
Note: The relation between object distance, image distance and focal length of a concave lens is given by the formula 1 / v - 1 / u = 1/f or 1/v = 1/f+ 1/u, where v distance of image from lens, u = distance of object from lens and f = focal length of lens
• So, according to the question l / v = 1/30 + 1/60 = 3/60
• ∴ v = - 20 cm
• A concave lens always forms a virtual, erect, and diminished image between the F and 2F of the lens.