Time and Distance and Time and work (UPSC) Part-II

Total Questions: 32

31. X, Y and Z can complete a piece of work individually in 6 hours, 8 hours and 8 hours respectively. However, only one person at a time can work in each hour and nobody can work for two consecutive hours. All are engaged to finish the work. What is the minimum amount of time that they will take to finish the work?         [2024-II]

Correct Answer: (c) 6 hours 45 minutes
Solution:X do more work / hour then y and z.
so, to get the work done in minimum possible time,
X have to do more number of hours.
∴ Working pattern would be.
X,(Y or Z), X, (Y or Z) . . .

X’s one hour work = 1/6 unit
Y’s one hour work = 1/8 unit

In 2 hour, amount of work finish = 1/6 + 1/8 = 4 + 3 / 24 = 7/24.

In 6 hour, work done = 3 Γ— 7 / 24

Remains work = 1 - 3 Γ— 7 / 24 = 3 / 24 = 1/8

X finish 1/8 work in 6 Γ— 1/8 hours = 45 minutes.

∴ Total time required = 6 hours 45 minutes.

32. A Question is given followed by two Statements I and II. Consider the Question and the Statements.             [2024-II]

A certain amount was distributed among X, Y and Z.
Question:
Who received the least amount?

Statement–I:
X received 45\frac{4}{5} of what Y and Z together received.

Statement–II:
Y received 27\frac{2}{7} of what X and Z together received.

 

Which one of the following is correct in respect of the above
Question and the Statements?

Correct Answer: (c) The Question can be answered by using both the Statements together, but cannot be answered using either Statement alone
Solution:S₁ : x = 4/5 (y + z) β‡’ 5x = 4 (y + z)

Sβ‚‚ : y = 2/7 (x + z) β‡’ 7y = 2 (x + z)

From S₁ and Sβ‚‚, By replacing y from two equations.

5x = 4 ( 2/7 (x + z) + z )

35x = 8x + 36z

27x = 36z

3x = 4z

∴ x > z

Again, by Replacing x from two equation.

7y = 2 ( 4/5 (y + z) + z )

35y = 8y + 18z

27y = 18z β‡’ 3y = 2z

∴ 3x = 6y = 4z

Hence, y < z < x.